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Ufumbuzi - Tiger algebra Suluhishaji

146099.20

146099.20

Tazama hatua Jifunze zaidi na Tiger Jaribu hili:

Maelezo kwa hatua

1. Weka fomula ya riba changamano

$c i (18545, 7, 2, 30)$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 18, 545$ , $r = 7 %$ , $n = 2$ , $t = 30$ .

$c i (18545, 7, 2, 30)$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 18, 545$ , $r = 7 %$ , $n = 2$ , $t = 30$ .

$P = 18545, r = 7 %, n = 2, t = 30$

$\frac{7}{100} = 0.07$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 18, 545$ , $r = 7 %$ , $n = 2$ , $t = 30$ .

$A = P {(1 + r / n)}^{(n t)}$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 18, 545$ , $r = 7 %$ , $n = 2$ , $t = 30$ .

$N e x t c o m p u t e r / n, n t, a n d {(1 + r / n)}^{(n t)} .$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 18, 545$ , $r = 7 %$ , $n = 2$ , $t = 30$ .

2. Hesabu kipengele cha ukuaji

$\frac{r}{n} = 0.035$

$n t = 60$

${(1 + r / n)}^{(n t)}$

$r / n = 0.035, n t = 60, {(1 + r / n)}^{(n t)} = 7.8780909008$ .

${(1 + r / n)}^{(n t)}$

${(1 + 0.035)}^{60} = 7.8780909008$

$r / n = 0.035, n t = 60, {(1 + r / n)}^{(n t)} = 7.8780909008$ .

$7.8780909008$

$r / n = 0.035, n t = 60, {(1 + r / n)}^{(n t)} = 7.8780909008$ .

3. Hesabu kiasi cha mwisho

$A = 146099.20$

$146099.20$

$18, 545 \cdot 7.8780909008 = 146099.20$ .

$146099.20$

$18, 545 \cdot 7.8780909008 = 146099.20$ .

$146099.20$

$18, 545 \cdot 7.8780909008 = 146099.20$ .

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Jifunze zaidi na Tiger

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Tiger algebra Suluhishaji

Ufumbuzi - Tiger algebra Suluhishaji

Maelezo kwa hatua

1. Weka fomula ya riba changamano

2. Hesabu kipengele cha ukuaji

3. Hesabu kiasi cha mwisho

Kwa nini kujifunza hii

Vigezo na mada

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