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Ufumbuzi - Tiger algebra Suluhishaji

42920.81

42920.81

Tazama hatua Jifunze zaidi na Tiger Jaribu hili:

Maelezo kwa hatua

1. Weka fomula ya riba changamano

$c i (18408, 8, 1, 11)$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 18, 408$ , $r = 8 %$ , $n = 1$ , $t = 11$ .

$c i (18408, 8, 1, 11)$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 18, 408$ , $r = 8 %$ , $n = 1$ , $t = 11$ .

$P = 18408, r = 8 %, n = 1, t = 11$

$\frac{8}{100} = 0.08$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 18, 408$ , $r = 8 %$ , $n = 1$ , $t = 11$ .

$A = P {(1 + r / n)}^{(n t)}$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 18, 408$ , $r = 8 %$ , $n = 1$ , $t = 11$ .

$N e x t c o m p u t e r / n, n t, a n d {(1 + r / n)}^{(n t)} .$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 18, 408$ , $r = 8 %$ , $n = 1$ , $t = 11$ .

2. Hesabu kipengele cha ukuaji

$\frac{r}{n} = 0.08$

$n t = 11$

${(1 + r / n)}^{(n t)}$

$r / n = 0.08, n t = 11, {(1 + r / n)}^{(n t)} = 2.3316389971$ .

${(1 + r / n)}^{(n t)}$

${(1 + 0.08)}^{11} = 2.3316389971$

$r / n = 0.08, n t = 11, {(1 + r / n)}^{(n t)} = 2.3316389971$ .

$2.3316389971$

$r / n = 0.08, n t = 11, {(1 + r / n)}^{(n t)} = 2.3316389971$ .

3. Hesabu kiasi cha mwisho

$A = 42920.81$

$42920.81$

$18, 408 \cdot 2.3316389971 = 42920.81$ .

$42920.81$

$18, 408 \cdot 2.3316389971 = 42920.81$ .

$42920.81$

$18, 408 \cdot 2.3316389971 = 42920.81$ .

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Jifunze zaidi na Tiger

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Tiger algebra Suluhishaji

Ufumbuzi - Tiger algebra Suluhishaji

Maelezo kwa hatua

1. Weka fomula ya riba changamano

2. Hesabu kipengele cha ukuaji

3. Hesabu kiasi cha mwisho

Kwa nini kujifunza hii

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