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Ufumbuzi - Tiger algebra Suluhishaji

281923.97

281923.97

Tazama hatua Jifunze zaidi na Tiger Jaribu hili:

Maelezo kwa hatua

1. Weka fomula ya riba changamano

$c i (18250, 11, 12, 25)$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 18, 250$ , $r = 11 %$ , $n = 12$ , $t = 25$ .

$c i (18250, 11, 12, 25)$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 18, 250$ , $r = 11 %$ , $n = 12$ , $t = 25$ .

$P = 18250, r = 11 %, n = 12, t = 25$

$\frac{11}{100} = 0.11$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 18, 250$ , $r = 11 %$ , $n = 12$ , $t = 25$ .

$A = P {(1 + r / n)}^{(n t)}$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 18, 250$ , $r = 11 %$ , $n = 12$ , $t = 25$ .

$N e x t c o m p u t e r / n, n t, a n d {(1 + r / n)}^{(n t)} .$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 18, 250$ , $r = 11 %$ , $n = 12$ , $t = 25$ .

2. Hesabu kipengele cha ukuaji

$\frac{r}{n} = 0.0091666667$

$n t = 300$

${(1 + r / n)}^{(n t)}$

$r / n = 0.0091666667, n t = 300, {(1 + r / n)}^{(n t)} = 15.447888589$ .

${(1 + r / n)}^{(n t)}$

${(1 + 0.0091666667)}^{300} = 15.447888589$

$r / n = 0.0091666667, n t = 300, {(1 + r / n)}^{(n t)} = 15.447888589$ .

$15.447888589$

$r / n = 0.0091666667, n t = 300, {(1 + r / n)}^{(n t)} = 15.447888589$ .

3. Hesabu kiasi cha mwisho

$A = 281923.97$

$281923.97$

$18, 250 \cdot 15.447888589 = 281923.97$ .

$281923.97$

$18, 250 \cdot 15.447888589 = 281923.97$ .

$281923.97$

$18, 250 \cdot 15.447888589 = 281923.97$ .

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Jifunze zaidi na Tiger

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Tiger algebra Suluhishaji

Ufumbuzi - Tiger algebra Suluhishaji

Maelezo kwa hatua

1. Weka fomula ya riba changamano

2. Hesabu kipengele cha ukuaji

3. Hesabu kiasi cha mwisho

Kwa nini kujifunza hii

Vigezo na mada

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