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Ufumbuzi - Tiger algebra Suluhishaji

1963.22

1963.22

Tazama hatua Jifunze zaidi na Tiger Jaribu hili:

Maelezo kwa hatua

1. Weka fomula ya riba changamano

$c i (1813, 4, 4, 2)$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 1, 813$ , $r = 4 %$ , $n = 4$ , $t = 2$ .

$c i (1813, 4, 4, 2)$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 1, 813$ , $r = 4 %$ , $n = 4$ , $t = 2$ .

$P = 1813, r = 4 %, n = 4, t = 2$

$\frac{4}{100} = 0.04$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 1, 813$ , $r = 4 %$ , $n = 4$ , $t = 2$ .

$A = P {(1 + r / n)}^{(n t)}$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 1, 813$ , $r = 4 %$ , $n = 4$ , $t = 2$ .

$N e x t c o m p u t e r / n, n t, a n d {(1 + r / n)}^{(n t)} .$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 1, 813$ , $r = 4 %$ , $n = 4$ , $t = 2$ .

2. Hesabu kipengele cha ukuaji

$\frac{r}{n} = 0.01$

$n t = 8$

${(1 + r / n)}^{(n t)}$

$r / n = 0.01, n t = 8, {(1 + r / n)}^{(n t)} = 1.0828567056$ .

${(1 + r / n)}^{(n t)}$

${(1 + 0.01)}^{8} = 1.0828567056$

$r / n = 0.01, n t = 8, {(1 + r / n)}^{(n t)} = 1.0828567056$ .

$1.0828567056$

$r / n = 0.01, n t = 8, {(1 + r / n)}^{(n t)} = 1.0828567056$ .

3. Hesabu kiasi cha mwisho

$A = 1963.22$

$1963.22$

$1, 813 \cdot 1.0828567056 = 1963.22$ .

$1963.22$

$1, 813 \cdot 1.0828567056 = 1963.22$ .

$1963.22$

$1, 813 \cdot 1.0828567056 = 1963.22$ .

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Jifunze zaidi na Tiger

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Tiger algebra Suluhishaji

Ufumbuzi - Tiger algebra Suluhishaji

Maelezo kwa hatua

1. Weka fomula ya riba changamano

2. Hesabu kipengele cha ukuaji

3. Hesabu kiasi cha mwisho

Kwa nini kujifunza hii

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