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Ufumbuzi - Tiger algebra Suluhishaji

76886.10

76886.10

Tazama hatua Jifunze zaidi na Tiger Jaribu hili:

Maelezo kwa hatua

1. Weka fomula ya riba changamano

$c i (18100, 15, 2, 10)$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 18, 100$ , $r = 15 %$ , $n = 2$ , $t = 10$ .

$c i (18100, 15, 2, 10)$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 18, 100$ , $r = 15 %$ , $n = 2$ , $t = 10$ .

$P = 18100, r = 15 %, n = 2, t = 10$

$\frac{15}{100} = 0.15$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 18, 100$ , $r = 15 %$ , $n = 2$ , $t = 10$ .

$A = P {(1 + r / n)}^{(n t)}$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 18, 100$ , $r = 15 %$ , $n = 2$ , $t = 10$ .

$N e x t c o m p u t e r / n, n t, a n d {(1 + r / n)}^{(n t)} .$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 18, 100$ , $r = 15 %$ , $n = 2$ , $t = 10$ .

2. Hesabu kipengele cha ukuaji

$\frac{r}{n} = 0.075$

$n t = 20$

${(1 + r / n)}^{(n t)}$

$r / n = 0.075, n t = 20, {(1 + r / n)}^{(n t)} = 4.2478511002$ .

${(1 + r / n)}^{(n t)}$

${(1 + 0.075)}^{20} = 4.2478511002$

$r / n = 0.075, n t = 20, {(1 + r / n)}^{(n t)} = 4.2478511002$ .

$4.2478511002$

$r / n = 0.075, n t = 20, {(1 + r / n)}^{(n t)} = 4.2478511002$ .

3. Hesabu kiasi cha mwisho

$A = 76886.10$

$76886.10$

$18, 100 \cdot 4.2478511002 = 76886.10$ .

$76886.10$

$18, 100 \cdot 4.2478511002 = 76886.10$ .

$76886.10$

$18, 100 \cdot 4.2478511002 = 76886.10$ .

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Jifunze zaidi na Tiger

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Tiger algebra Suluhishaji

Ufumbuzi - Tiger algebra Suluhishaji

Maelezo kwa hatua

1. Weka fomula ya riba changamano

2. Hesabu kipengele cha ukuaji

3. Hesabu kiasi cha mwisho

Kwa nini kujifunza hii

Vigezo na mada

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