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Ufumbuzi - Tiger algebra Suluhishaji

628234.16

628234.16

Tazama hatua Jifunze zaidi na Tiger Jaribu hili:

Maelezo kwa hatua

1. Weka fomula ya riba changamano

$c i (18099, 12, 4, 30)$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 18, 099$ , $r = 12 %$ , $n = 4$ , $t = 30$ .

$c i (18099, 12, 4, 30)$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 18, 099$ , $r = 12 %$ , $n = 4$ , $t = 30$ .

$P = 18099, r = 12 %, n = 4, t = 30$

$\frac{12}{100} = 0.12$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 18, 099$ , $r = 12 %$ , $n = 4$ , $t = 30$ .

$A = P {(1 + r / n)}^{(n t)}$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 18, 099$ , $r = 12 %$ , $n = 4$ , $t = 30$ .

$N e x t c o m p u t e r / n, n t, a n d {(1 + r / n)}^{(n t)} .$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 18, 099$ , $r = 12 %$ , $n = 4$ , $t = 30$ .

2. Hesabu kipengele cha ukuaji

$\frac{r}{n} = 0.03$

$n t = 120$

${(1 + r / n)}^{(n t)}$

$r / n = 0.03, n t = 120, {(1 + r / n)}^{(n t)} = 34.7109871356$ .

${(1 + r / n)}^{(n t)}$

${(1 + 0.03)}^{120} = 34.7109871356$

$r / n = 0.03, n t = 120, {(1 + r / n)}^{(n t)} = 34.7109871356$ .

$34.7109871356$

$r / n = 0.03, n t = 120, {(1 + r / n)}^{(n t)} = 34.7109871356$ .

3. Hesabu kiasi cha mwisho

$A = 628234.16$

$628234.16$

$18, 099 \cdot 34.7109871356 = 628234.16$ .

$628234.16$

$18, 099 \cdot 34.7109871356 = 628234.16$ .

$628234.16$

$18, 099 \cdot 34.7109871356 = 628234.16$ .

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Tiger algebra Suluhishaji

Ufumbuzi - Tiger algebra Suluhishaji

Maelezo kwa hatua

1. Weka fomula ya riba changamano

2. Hesabu kipengele cha ukuaji

3. Hesabu kiasi cha mwisho

Kwa nini kujifunza hii

Vigezo na mada

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