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Ufumbuzi - Tiger algebra Suluhishaji

88462.98

88462.98

Tazama hatua Jifunze zaidi na Tiger Jaribu hili:

Maelezo kwa hatua

1. Weka fomula ya riba changamano

$c i (18061, 13, 1, 13)$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 18, 061$ , $r = 13 %$ , $n = 1$ , $t = 13$ .

$c i (18061, 13, 1, 13)$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 18, 061$ , $r = 13 %$ , $n = 1$ , $t = 13$ .

$P = 18061, r = 13 %, n = 1, t = 13$

$\frac{13}{100} = 0.13$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 18, 061$ , $r = 13 %$ , $n = 1$ , $t = 13$ .

$A = P {(1 + r / n)}^{(n t)}$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 18, 061$ , $r = 13 %$ , $n = 1$ , $t = 13$ .

$N e x t c o m p u t e r / n, n t, a n d {(1 + r / n)}^{(n t)} .$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 18, 061$ , $r = 13 %$ , $n = 1$ , $t = 13$ .

2. Hesabu kipengele cha ukuaji

$\frac{r}{n} = 0.13$

$n t = 13$

${(1 + r / n)}^{(n t)}$

$r / n = 0.13, n t = 13, {(1 + r / n)}^{(n t)} = 4.8980111032$ .

${(1 + r / n)}^{(n t)}$

${(1 + 0.13)}^{13} = 4.8980111032$

$r / n = 0.13, n t = 13, {(1 + r / n)}^{(n t)} = 4.8980111032$ .

$4.8980111032$

$r / n = 0.13, n t = 13, {(1 + r / n)}^{(n t)} = 4.8980111032$ .

3. Hesabu kiasi cha mwisho

$A = 88462.98$

$88462.98$

$18, 061 \cdot 4.8980111032 = 88462.98$ .

$88462.98$

$18, 061 \cdot 4.8980111032 = 88462.98$ .

$88462.98$

$18, 061 \cdot 4.8980111032 = 88462.98$ .

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Jifunze zaidi na Tiger

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Tiger algebra Suluhishaji

Ufumbuzi - Tiger algebra Suluhishaji

Maelezo kwa hatua

1. Weka fomula ya riba changamano

2. Hesabu kipengele cha ukuaji

3. Hesabu kiasi cha mwisho

Kwa nini kujifunza hii

Vigezo na mada

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