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Ufumbuzi - Tiger algebra Suluhishaji

20799.10

20799.10

Tazama hatua Jifunze zaidi na Tiger Jaribu hili:

Maelezo kwa hatua

1. Weka fomula ya riba changamano

$c i (17935, 5, 2, 3)$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 17, 935$ , $r = 5 %$ , $n = 2$ , $t = 3$ .

$c i (17935, 5, 2, 3)$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 17, 935$ , $r = 5 %$ , $n = 2$ , $t = 3$ .

$P = 17935, r = 5 %, n = 2, t = 3$

$\frac{5}{100} = 0.05$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 17, 935$ , $r = 5 %$ , $n = 2$ , $t = 3$ .

$A = P {(1 + r / n)}^{(n t)}$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 17, 935$ , $r = 5 %$ , $n = 2$ , $t = 3$ .

$N e x t c o m p u t e r / n, n t, a n d {(1 + r / n)}^{(n t)} .$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 17, 935$ , $r = 5 %$ , $n = 2$ , $t = 3$ .

2. Hesabu kipengele cha ukuaji

$\frac{r}{n} = 0.025$

$n t = 6$

${(1 + r / n)}^{(n t)}$

$r / n = 0.025, n t = 6, {(1 + r / n)}^{(n t)} = 1.1596934182$ .

${(1 + r / n)}^{(n t)}$

${(1 + 0.025)}^{6} = 1.1596934182$

$r / n = 0.025, n t = 6, {(1 + r / n)}^{(n t)} = 1.1596934182$ .

$1.1596934182$

$r / n = 0.025, n t = 6, {(1 + r / n)}^{(n t)} = 1.1596934182$ .

3. Hesabu kiasi cha mwisho

$A = 20799.10$

$20799.10$

$17, 935 \cdot 1.1596934182 = 20799.10$ .

$20799.10$

$17, 935 \cdot 1.1596934182 = 20799.10$ .

$20799.10$

$17, 935 \cdot 1.1596934182 = 20799.10$ .

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Tiger algebra Suluhishaji

Ufumbuzi - Tiger algebra Suluhishaji

Maelezo kwa hatua

1. Weka fomula ya riba changamano

2. Hesabu kipengele cha ukuaji

3. Hesabu kiasi cha mwisho

Kwa nini kujifunza hii

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