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Ufumbuzi - Tiger algebra Suluhishaji

195897.27

195897.27

Tazama hatua Jifunze zaidi na Tiger Jaribu hili:

Maelezo kwa hatua

1. Weka fomula ya riba changamano

$c i (17717, 9, 4, 27)$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 17, 717$ , $r = 9 %$ , $n = 4$ , $t = 27$ .

$c i (17717, 9, 4, 27)$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 17, 717$ , $r = 9 %$ , $n = 4$ , $t = 27$ .

$P = 17717, r = 9 %, n = 4, t = 27$

$\frac{9}{100} = 0.09$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 17, 717$ , $r = 9 %$ , $n = 4$ , $t = 27$ .

$A = P {(1 + r / n)}^{(n t)}$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 17, 717$ , $r = 9 %$ , $n = 4$ , $t = 27$ .

$N e x t c o m p u t e r / n, n t, a n d {(1 + r / n)}^{(n t)} .$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 17, 717$ , $r = 9 %$ , $n = 4$ , $t = 27$ .

2. Hesabu kipengele cha ukuaji

$\frac{r}{n} = 0.0225$

$n t = 108$

${(1 + r / n)}^{(n t)}$

$r / n = 0.0225, n t = 108, {(1 + r / n)}^{(n t)} = 11.0570227045$ .

${(1 + r / n)}^{(n t)}$

${(1 + 0.0225)}^{108} = 11.0570227045$

$r / n = 0.0225, n t = 108, {(1 + r / n)}^{(n t)} = 11.0570227045$ .

$11.0570227045$

$r / n = 0.0225, n t = 108, {(1 + r / n)}^{(n t)} = 11.0570227045$ .

3. Hesabu kiasi cha mwisho

$A = 195897.27$

$195897.27$

$17, 717 \cdot 11.0570227045 = 195897.27$ .

$195897.27$

$17, 717 \cdot 11.0570227045 = 195897.27$ .

$195897.27$

$17, 717 \cdot 11.0570227045 = 195897.27$ .

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Tiger algebra Suluhishaji

Ufumbuzi - Tiger algebra Suluhishaji

Maelezo kwa hatua

1. Weka fomula ya riba changamano

2. Hesabu kipengele cha ukuaji

3. Hesabu kiasi cha mwisho

Kwa nini kujifunza hii

Vigezo na mada

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