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Ufumbuzi - Tiger algebra Suluhishaji

83480.25

83480.25

Tazama hatua Jifunze zaidi na Tiger Jaribu hili:

Maelezo kwa hatua

1. Weka fomula ya riba changamano

$c i (17690, 13, 12, 12)$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 17, 690$ , $r = 13 %$ , $n = 12$ , $t = 12$ .

$c i (17690, 13, 12, 12)$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 17, 690$ , $r = 13 %$ , $n = 12$ , $t = 12$ .

$P = 17690, r = 13 %, n = 12, t = 12$

$\frac{13}{100} = 0.13$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 17, 690$ , $r = 13 %$ , $n = 12$ , $t = 12$ .

$A = P {(1 + r / n)}^{(n t)}$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 17, 690$ , $r = 13 %$ , $n = 12$ , $t = 12$ .

$N e x t c o m p u t e r / n, n t, a n d {(1 + r / n)}^{(n t)} .$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 17, 690$ , $r = 13 %$ , $n = 12$ , $t = 12$ .

2. Hesabu kipengele cha ukuaji

$\frac{r}{n} = 0.0108333333$

$n t = 144$

${(1 + r / n)}^{(n t)}$

$r / n = 0.0108333333, n t = 144, {(1 + r / n)}^{(n t)} = 4.7190642895$ .

${(1 + r / n)}^{(n t)}$

${(1 + 0.0108333333)}^{144} = 4.7190642895$

$r / n = 0.0108333333, n t = 144, {(1 + r / n)}^{(n t)} = 4.7190642895$ .

$4.7190642895$

$r / n = 0.0108333333, n t = 144, {(1 + r / n)}^{(n t)} = 4.7190642895$ .

3. Hesabu kiasi cha mwisho

$A = 83480.25$

$83480.25$

$17, 690 \cdot 4.7190642895 = 83480.25$ .

$83480.25$

$17, 690 \cdot 4.7190642895 = 83480.25$ .

$83480.25$

$17, 690 \cdot 4.7190642895 = 83480.25$ .

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Jifunze zaidi na Tiger

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Tiger algebra Suluhishaji

Ufumbuzi - Tiger algebra Suluhishaji

Maelezo kwa hatua

1. Weka fomula ya riba changamano

2. Hesabu kipengele cha ukuaji

3. Hesabu kiasi cha mwisho

Kwa nini kujifunza hii

Vigezo na mada

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