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Ufumbuzi - Tiger algebra Suluhishaji

145875.39

145875.39

Tazama hatua Jifunze zaidi na Tiger Jaribu hili:

Maelezo kwa hatua

1. Weka fomula ya riba changamano

$c i (17636, 9, 2, 24)$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 17, 636$ , $r = 9 %$ , $n = 2$ , $t = 24$ .

$c i (17636, 9, 2, 24)$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 17, 636$ , $r = 9 %$ , $n = 2$ , $t = 24$ .

$P = 17636, r = 9 %, n = 2, t = 24$

$\frac{9}{100} = 0.09$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 17, 636$ , $r = 9 %$ , $n = 2$ , $t = 24$ .

$A = P {(1 + r / n)}^{(n t)}$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 17, 636$ , $r = 9 %$ , $n = 2$ , $t = 24$ .

$N e x t c o m p u t e r / n, n t, a n d {(1 + r / n)}^{(n t)} .$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 17, 636$ , $r = 9 %$ , $n = 2$ , $t = 24$ .

2. Hesabu kipengele cha ukuaji

$\frac{r}{n} = 0.045$

$n t = 48$

${(1 + r / n)}^{(n t)}$

$r / n = 0.045, n t = 48, {(1 + r / n)}^{(n t)} = 8.2714555734$ .

${(1 + r / n)}^{(n t)}$

${(1 + 0.045)}^{48} = 8.2714555734$

$r / n = 0.045, n t = 48, {(1 + r / n)}^{(n t)} = 8.2714555734$ .

$8.2714555734$

$r / n = 0.045, n t = 48, {(1 + r / n)}^{(n t)} = 8.2714555734$ .

3. Hesabu kiasi cha mwisho

$A = 145875.39$

$145875.39$

$17, 636 \cdot 8.2714555734 = 145875.39$ .

$145875.39$

$17, 636 \cdot 8.2714555734 = 145875.39$ .

$145875.39$

$17, 636 \cdot 8.2714555734 = 145875.39$ .

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Tiger algebra Suluhishaji

Ufumbuzi - Tiger algebra Suluhishaji

Maelezo kwa hatua

1. Weka fomula ya riba changamano

2. Hesabu kipengele cha ukuaji

3. Hesabu kiasi cha mwisho

Kwa nini kujifunza hii

Vigezo na mada

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