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Ufumbuzi - Tiger algebra Suluhishaji

28283.28

28283.28

Tazama hatua Jifunze zaidi na Tiger Jaribu hili:

Maelezo kwa hatua

1. Weka fomula ya riba changamano

$c i (17543, 12, 12, 4)$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 17, 543$ , $r = 12 %$ , $n = 12$ , $t = 4$ .

$c i (17543, 12, 12, 4)$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 17, 543$ , $r = 12 %$ , $n = 12$ , $t = 4$ .

$P = 17543, r = 12 %, n = 12, t = 4$

$\frac{12}{100} = 0.12$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 17, 543$ , $r = 12 %$ , $n = 12$ , $t = 4$ .

$A = P {(1 + r / n)}^{(n t)}$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 17, 543$ , $r = 12 %$ , $n = 12$ , $t = 4$ .

$N e x t c o m p u t e r / n, n t, a n d {(1 + r / n)}^{(n t)} .$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 17, 543$ , $r = 12 %$ , $n = 12$ , $t = 4$ .

2. Hesabu kipengele cha ukuaji

$\frac{r}{n} = 0.01$

$n t = 48$

${(1 + r / n)}^{(n t)}$

$r / n = 0.01, n t = 48, {(1 + r / n)}^{(n t)} = 1.6122260777$ .

${(1 + r / n)}^{(n t)}$

${(1 + 0.01)}^{48} = 1.6122260777$

$r / n = 0.01, n t = 48, {(1 + r / n)}^{(n t)} = 1.6122260777$ .

$1.6122260777$

$r / n = 0.01, n t = 48, {(1 + r / n)}^{(n t)} = 1.6122260777$ .

3. Hesabu kiasi cha mwisho

$A = 28283.28$

$28283.28$

$17, 543 \cdot 1.6122260777 = 28283.28$ .

$28283.28$

$17, 543 \cdot 1.6122260777 = 28283.28$ .

$28283.28$

$17, 543 \cdot 1.6122260777 = 28283.28$ .

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Jifunze zaidi na Tiger

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Tiger algebra Suluhishaji

Ufumbuzi - Tiger algebra Suluhishaji

Maelezo kwa hatua

1. Weka fomula ya riba changamano

2. Hesabu kipengele cha ukuaji

3. Hesabu kiasi cha mwisho

Kwa nini kujifunza hii

Vigezo na mada

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