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Ufumbuzi - Tiger algebra Suluhishaji

19101.15

19101.15

Tazama hatua Jifunze zaidi na Tiger Jaribu hili:

Maelezo kwa hatua

1. Weka fomula ya riba changamano

$c i (17463, 3, 4, 3)$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 17, 463$ , $r = 3 %$ , $n = 4$ , $t = 3$ .

$c i (17463, 3, 4, 3)$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 17, 463$ , $r = 3 %$ , $n = 4$ , $t = 3$ .

$P = 17463, r = 3 %, n = 4, t = 3$

$\frac{3}{100} = 0.03$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 17, 463$ , $r = 3 %$ , $n = 4$ , $t = 3$ .

$A = P {(1 + r / n)}^{(n t)}$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 17, 463$ , $r = 3 %$ , $n = 4$ , $t = 3$ .

$N e x t c o m p u t e r / n, n t, a n d {(1 + r / n)}^{(n t)} .$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 17, 463$ , $r = 3 %$ , $n = 4$ , $t = 3$ .

2. Hesabu kipengele cha ukuaji

$\frac{r}{n} = 0.0075$

$n t = 12$

${(1 + r / n)}^{(n t)}$

$r / n = 0.0075, n t = 12, {(1 + r / n)}^{(n t)} = 1.0938068977$ .

${(1 + r / n)}^{(n t)}$

${(1 + 0.0075)}^{12} = 1.0938068977$

$r / n = 0.0075, n t = 12, {(1 + r / n)}^{(n t)} = 1.0938068977$ .

$1.0938068977$

$r / n = 0.0075, n t = 12, {(1 + r / n)}^{(n t)} = 1.0938068977$ .

3. Hesabu kiasi cha mwisho

$A = 19101.15$

$19101.15$

$17, 463 \cdot 1.0938068977 = 19101.15$ .

$19101.15$

$17, 463 \cdot 1.0938068977 = 19101.15$ .

$19101.15$

$17, 463 \cdot 1.0938068977 = 19101.15$ .

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Jifunze zaidi na Tiger

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Tiger algebra Suluhishaji

Ufumbuzi - Tiger algebra Suluhishaji

Maelezo kwa hatua

1. Weka fomula ya riba changamano

2. Hesabu kipengele cha ukuaji

3. Hesabu kiasi cha mwisho

Kwa nini kujifunza hii

Vigezo na mada

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