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Ufumbuzi - Tiger algebra Suluhishaji

5725.40

5725.40

Tazama hatua Jifunze zaidi na Tiger Jaribu hili:

Maelezo kwa hatua

1. Weka fomula ya riba changamano

$c i (1745, 8, 4, 15)$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 1, 745$ , $r = 8 %$ , $n = 4$ , $t = 15$ .

$c i (1745, 8, 4, 15)$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 1, 745$ , $r = 8 %$ , $n = 4$ , $t = 15$ .

$P = 1745, r = 8 %, n = 4, t = 15$

$\frac{8}{100} = 0.08$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 1, 745$ , $r = 8 %$ , $n = 4$ , $t = 15$ .

$A = P {(1 + r / n)}^{(n t)}$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 1, 745$ , $r = 8 %$ , $n = 4$ , $t = 15$ .

$N e x t c o m p u t e r / n, n t, a n d {(1 + r / n)}^{(n t)} .$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 1, 745$ , $r = 8 %$ , $n = 4$ , $t = 15$ .

2. Hesabu kipengele cha ukuaji

$\frac{r}{n} = 0.02$

$n t = 60$

${(1 + r / n)}^{(n t)}$

$r / n = 0.02, n t = 60, {(1 + r / n)}^{(n t)} = 3.2810307884$ .

${(1 + r / n)}^{(n t)}$

${(1 + 0.02)}^{60} = 3.2810307884$

$r / n = 0.02, n t = 60, {(1 + r / n)}^{(n t)} = 3.2810307884$ .

$3.2810307884$

$r / n = 0.02, n t = 60, {(1 + r / n)}^{(n t)} = 3.2810307884$ .

3. Hesabu kiasi cha mwisho

$A = 5725.40$

$5725.40$

$1, 745 \cdot 3.2810307884 = 5725.40$ .

$5725.40$

$1, 745 \cdot 3.2810307884 = 5725.40$ .

$5725.40$

$1, 745 \cdot 3.2810307884 = 5725.40$ .

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Jifunze zaidi na Tiger

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Tiger algebra Suluhishaji

Ufumbuzi - Tiger algebra Suluhishaji

Maelezo kwa hatua

1. Weka fomula ya riba changamano

2. Hesabu kipengele cha ukuaji

3. Hesabu kiasi cha mwisho

Kwa nini kujifunza hii

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