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Ufumbuzi - Tiger algebra Suluhishaji

3662.28

3662.28

Tazama hatua Jifunze zaidi na Tiger Jaribu hili:

Maelezo kwa hatua

1. Weka fomula ya riba changamano

$c i (1738, 15, 12, 5)$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 1, 738$ , $r = 15 %$ , $n = 12$ , $t = 5$ .

$c i (1738, 15, 12, 5)$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 1, 738$ , $r = 15 %$ , $n = 12$ , $t = 5$ .

$P = 1738, r = 15 %, n = 12, t = 5$

$\frac{15}{100} = 0.15$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 1, 738$ , $r = 15 %$ , $n = 12$ , $t = 5$ .

$A = P {(1 + r / n)}^{(n t)}$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 1, 738$ , $r = 15 %$ , $n = 12$ , $t = 5$ .

$N e x t c o m p u t e r / n, n t, a n d {(1 + r / n)}^{(n t)} .$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 1, 738$ , $r = 15 %$ , $n = 12$ , $t = 5$ .

2. Hesabu kipengele cha ukuaji

$\frac{r}{n} = 0.0125$

$n t = 60$

${(1 + r / n)}^{(n t)}$

$r / n = 0.0125, n t = 60, {(1 + r / n)}^{(n t)} = 2.107181347$ .

${(1 + r / n)}^{(n t)}$

${(1 + 0.0125)}^{60} = 2.107181347$

$r / n = 0.0125, n t = 60, {(1 + r / n)}^{(n t)} = 2.107181347$ .

$2.107181347$

$r / n = 0.0125, n t = 60, {(1 + r / n)}^{(n t)} = 2.107181347$ .

3. Hesabu kiasi cha mwisho

$A = 3662.28$

$3662.28$

$1, 738 \cdot 2.107181347 = 3662.28$ .

$3662.28$

$1, 738 \cdot 2.107181347 = 3662.28$ .

$3662.28$

$1, 738 \cdot 2.107181347 = 3662.28$ .

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Jifunze zaidi na Tiger

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Tiger algebra Suluhishaji

Ufumbuzi - Tiger algebra Suluhishaji

Maelezo kwa hatua

1. Weka fomula ya riba changamano

2. Hesabu kipengele cha ukuaji

3. Hesabu kiasi cha mwisho

Kwa nini kujifunza hii

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