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Ufumbuzi - Tiger algebra Suluhishaji

44972.79

44972.79

Tazama hatua Jifunze zaidi na Tiger Jaribu hili:

Maelezo kwa hatua

1. Weka fomula ya riba changamano

$c i (17261, 6, 12, 16)$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 17, 261$ , $r = 6 %$ , $n = 12$ , $t = 16$ .

$c i (17261, 6, 12, 16)$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 17, 261$ , $r = 6 %$ , $n = 12$ , $t = 16$ .

$P = 17261, r = 6 %, n = 12, t = 16$

$\frac{6}{100} = 0.06$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 17, 261$ , $r = 6 %$ , $n = 12$ , $t = 16$ .

$A = P {(1 + r / n)}^{(n t)}$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 17, 261$ , $r = 6 %$ , $n = 12$ , $t = 16$ .

$N e x t c o m p u t e r / n, n t, a n d {(1 + r / n)}^{(n t)} .$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 17, 261$ , $r = 6 %$ , $n = 12$ , $t = 16$ .

2. Hesabu kipengele cha ukuaji

$\frac{r}{n} = 0.005$

$n t = 192$

${(1 + r / n)}^{(n t)}$

$r / n = 0.005, n t = 192, {(1 + r / n)}^{(n t)} = 2.6054566833$ .

${(1 + r / n)}^{(n t)}$

${(1 + 0.005)}^{192} = 2.6054566833$

$r / n = 0.005, n t = 192, {(1 + r / n)}^{(n t)} = 2.6054566833$ .

$2.6054566833$

$r / n = 0.005, n t = 192, {(1 + r / n)}^{(n t)} = 2.6054566833$ .

3. Hesabu kiasi cha mwisho

$A = 44972.79$

$44972.79$

$17, 261 \cdot 2.6054566833 = 44972.79$ .

$44972.79$

$17, 261 \cdot 2.6054566833 = 44972.79$ .

$44972.79$

$17, 261 \cdot 2.6054566833 = 44972.79$ .

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Jifunze zaidi na Tiger

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Tiger algebra Suluhishaji

Ufumbuzi - Tiger algebra Suluhishaji

Maelezo kwa hatua

1. Weka fomula ya riba changamano

2. Hesabu kipengele cha ukuaji

3. Hesabu kiasi cha mwisho

Kwa nini kujifunza hii

Vigezo na mada

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