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Ufumbuzi - Tiger algebra Suluhishaji

202662.01

202662.01

Tazama hatua Jifunze zaidi na Tiger Jaribu hili:

Maelezo kwa hatua

1. Weka fomula ya riba changamano

$c i (17229, 9, 2, 28)$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 17, 229$ , $r = 9 %$ , $n = 2$ , $t = 28$ .

$c i (17229, 9, 2, 28)$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 17, 229$ , $r = 9 %$ , $n = 2$ , $t = 28$ .

$P = 17229, r = 9 %, n = 2, t = 28$

$\frac{9}{100} = 0.09$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 17, 229$ , $r = 9 %$ , $n = 2$ , $t = 28$ .

$A = P {(1 + r / n)}^{(n t)}$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 17, 229$ , $r = 9 %$ , $n = 2$ , $t = 28$ .

$N e x t c o m p u t e r / n, n t, a n d {(1 + r / n)}^{(n t)} .$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 17, 229$ , $r = 9 %$ , $n = 2$ , $t = 28$ .

2. Hesabu kipengele cha ukuaji

$\frac{r}{n} = 0.045$

$n t = 56$

${(1 + r / n)}^{(n t)}$

$r / n = 0.045, n t = 56, {(1 + r / n)}^{(n t)} = 11.76284204$ .

${(1 + r / n)}^{(n t)}$

${(1 + 0.045)}^{56} = 11.76284204$

$r / n = 0.045, n t = 56, {(1 + r / n)}^{(n t)} = 11.76284204$ .

$11.76284204$

$r / n = 0.045, n t = 56, {(1 + r / n)}^{(n t)} = 11.76284204$ .

3. Hesabu kiasi cha mwisho

$A = 202662.01$

$202662.01$

$17, 229 \cdot 11.76284204 = 202662.01$ .

$202662.01$

$17, 229 \cdot 11.76284204 = 202662.01$ .

$202662.01$

$17, 229 \cdot 11.76284204 = 202662.01$ .

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Jifunze zaidi na Tiger

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Tiger algebra Suluhishaji

Ufumbuzi - Tiger algebra Suluhishaji

Maelezo kwa hatua

1. Weka fomula ya riba changamano

2. Hesabu kipengele cha ukuaji

3. Hesabu kiasi cha mwisho

Kwa nini kujifunza hii

Vigezo na mada

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