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Ufumbuzi - Tiger algebra Suluhishaji

21253.60

21253.60

Tazama hatua Jifunze zaidi na Tiger Jaribu hili:

Maelezo kwa hatua

1. Weka fomula ya riba changamano

$c i (16906, 1, 1, 23)$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 16, 906$ , $r = 1 %$ , $n = 1$ , $t = 23$ .

$c i (16906, 1, 1, 23)$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 16, 906$ , $r = 1 %$ , $n = 1$ , $t = 23$ .

$P = 16906, r = 1 %, n = 1, t = 23$

$\frac{1}{100} = 0.01$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 16, 906$ , $r = 1 %$ , $n = 1$ , $t = 23$ .

$A = P {(1 + r / n)}^{(n t)}$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 16, 906$ , $r = 1 %$ , $n = 1$ , $t = 23$ .

$N e x t c o m p u t e r / n, n t, a n d {(1 + r / n)}^{(n t)} .$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 16, 906$ , $r = 1 %$ , $n = 1$ , $t = 23$ .

2. Hesabu kipengele cha ukuaji

$\frac{r}{n} = 0.01$

$n t = 23$

${(1 + r / n)}^{(n t)}$

$r / n = 0.01, n t = 23, {(1 + r / n)}^{(n t)} = 1.2571630183$ .

${(1 + r / n)}^{(n t)}$

${(1 + 0.01)}^{23} = 1.2571630183$

$r / n = 0.01, n t = 23, {(1 + r / n)}^{(n t)} = 1.2571630183$ .

$1.2571630183$

$r / n = 0.01, n t = 23, {(1 + r / n)}^{(n t)} = 1.2571630183$ .

3. Hesabu kiasi cha mwisho

$A = 21253.60$

$21253.60$

$16, 906 \cdot 1.2571630183 = 21253.60$ .

$21253.60$

$16, 906 \cdot 1.2571630183 = 21253.60$ .

$21253.60$

$16, 906 \cdot 1.2571630183 = 21253.60$ .

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Tiger algebra Suluhishaji

Ufumbuzi - Tiger algebra Suluhishaji

Maelezo kwa hatua

1. Weka fomula ya riba changamano

2. Hesabu kipengele cha ukuaji

3. Hesabu kiasi cha mwisho

Kwa nini kujifunza hii

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