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Ufumbuzi - Tiger algebra Suluhishaji

330335.54

330335.54

Tazama hatua Jifunze zaidi na Tiger Jaribu hili:

Maelezo kwa hatua

1. Weka fomula ya riba changamano

$c i (16881, 13, 12, 23)$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 16, 881$ , $r = 13 %$ , $n = 12$ , $t = 23$ .

$c i (16881, 13, 12, 23)$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 16, 881$ , $r = 13 %$ , $n = 12$ , $t = 23$ .

$P = 16881, r = 13 %, n = 12, t = 23$

$\frac{13}{100} = 0.13$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 16, 881$ , $r = 13 %$ , $n = 12$ , $t = 23$ .

$A = P {(1 + r / n)}^{(n t)}$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 16, 881$ , $r = 13 %$ , $n = 12$ , $t = 23$ .

$N e x t c o m p u t e r / n, n t, a n d {(1 + r / n)}^{(n t)} .$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 16, 881$ , $r = 13 %$ , $n = 12$ , $t = 23$ .

2. Hesabu kipengele cha ukuaji

$\frac{r}{n} = 0.0108333333$

$n t = 276$

${(1 + r / n)}^{(n t)}$

$r / n = 0.0108333333, n t = 276, {(1 + r / n)}^{(n t)} = 19.5684816803$ .

${(1 + r / n)}^{(n t)}$

${(1 + 0.0108333333)}^{276} = 19.5684816803$

$r / n = 0.0108333333, n t = 276, {(1 + r / n)}^{(n t)} = 19.5684816803$ .

$19.5684816803$

$r / n = 0.0108333333, n t = 276, {(1 + r / n)}^{(n t)} = 19.5684816803$ .

3. Hesabu kiasi cha mwisho

$A = 330335.54$

$330335.54$

$16, 881 \cdot 19.5684816803 = 330335.54$ .

$330335.54$

$16, 881 \cdot 19.5684816803 = 330335.54$ .

$330335.54$

$16, 881 \cdot 19.5684816803 = 330335.54$ .

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Jifunze zaidi na Tiger

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Tiger algebra Suluhishaji

Ufumbuzi - Tiger algebra Suluhishaji

Maelezo kwa hatua

1. Weka fomula ya riba changamano

2. Hesabu kipengele cha ukuaji

3. Hesabu kiasi cha mwisho

Kwa nini kujifunza hii

Vigezo na mada

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