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Ufumbuzi - Tiger algebra Suluhishaji

77990.71

77990.71

Tazama hatua Jifunze zaidi na Tiger Jaribu hili:

Maelezo kwa hatua

1. Weka fomula ya riba changamano

$c i (16769, 12, 4, 13)$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 16, 769$ , $r = 12 %$ , $n = 4$ , $t = 13$ .

$c i (16769, 12, 4, 13)$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 16, 769$ , $r = 12 %$ , $n = 4$ , $t = 13$ .

$P = 16769, r = 12 %, n = 4, t = 13$

$\frac{12}{100} = 0.12$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 16, 769$ , $r = 12 %$ , $n = 4$ , $t = 13$ .

$A = P {(1 + r / n)}^{(n t)}$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 16, 769$ , $r = 12 %$ , $n = 4$ , $t = 13$ .

$N e x t c o m p u t e r / n, n t, a n d {(1 + r / n)}^{(n t)} .$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 16, 769$ , $r = 12 %$ , $n = 4$ , $t = 13$ .

2. Hesabu kipengele cha ukuaji

$\frac{r}{n} = 0.03$

$n t = 52$

${(1 + r / n)}^{(n t)}$

$r / n = 0.03, n t = 52, {(1 + r / n)}^{(n t)} = 4.6508858952$ .

${(1 + r / n)}^{(n t)}$

${(1 + 0.03)}^{52} = 4.6508858952$

$r / n = 0.03, n t = 52, {(1 + r / n)}^{(n t)} = 4.6508858952$ .

$4.6508858952$

$r / n = 0.03, n t = 52, {(1 + r / n)}^{(n t)} = 4.6508858952$ .

3. Hesabu kiasi cha mwisho

$A = 77990.71$

$77990.71$

$16, 769 \cdot 4.6508858952 = 77990.71$ .

$77990.71$

$16, 769 \cdot 4.6508858952 = 77990.71$ .

$77990.71$

$16, 769 \cdot 4.6508858952 = 77990.71$ .

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Tiger algebra Suluhishaji

Ufumbuzi - Tiger algebra Suluhishaji

Maelezo kwa hatua

1. Weka fomula ya riba changamano

2. Hesabu kipengele cha ukuaji

3. Hesabu kiasi cha mwisho

Kwa nini kujifunza hii

Vigezo na mada

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