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Ufumbuzi - Tiger algebra Suluhishaji

215338.90

215338.90

Tazama hatua Jifunze zaidi na Tiger Jaribu hili:

Maelezo kwa hatua

1. Weka fomula ya riba changamano

$c i (16764, 9, 2, 29)$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 16, 764$ , $r = 9 %$ , $n = 2$ , $t = 29$ .

$c i (16764, 9, 2, 29)$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 16, 764$ , $r = 9 %$ , $n = 2$ , $t = 29$ .

$P = 16764, r = 9 %, n = 2, t = 29$

$\frac{9}{100} = 0.09$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 16, 764$ , $r = 9 %$ , $n = 2$ , $t = 29$ .

$A = P {(1 + r / n)}^{(n t)}$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 16, 764$ , $r = 9 %$ , $n = 2$ , $t = 29$ .

$N e x t c o m p u t e r / n, n t, a n d {(1 + r / n)}^{(n t)} .$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 16, 764$ , $r = 9 %$ , $n = 2$ , $t = 29$ .

2. Hesabu kipengele cha ukuaji

$\frac{r}{n} = 0.045$

$n t = 58$

${(1 + r / n)}^{(n t)}$

$r / n = 0.045, n t = 58, {(1 + r / n)}^{(n t)} = 12.8453175787$ .

${(1 + r / n)}^{(n t)}$

${(1 + 0.045)}^{58} = 12.8453175787$

$r / n = 0.045, n t = 58, {(1 + r / n)}^{(n t)} = 12.8453175787$ .

$12.8453175787$

$r / n = 0.045, n t = 58, {(1 + r / n)}^{(n t)} = 12.8453175787$ .

3. Hesabu kiasi cha mwisho

$A = 215338.90$

$215338.90$

$16, 764 \cdot 12.8453175787 = 215338.90$ .

$215338.90$

$16, 764 \cdot 12.8453175787 = 215338.90$ .

$215338.90$

$16, 764 \cdot 12.8453175787 = 215338.90$ .

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Tiger algebra Suluhishaji

Ufumbuzi - Tiger algebra Suluhishaji

Maelezo kwa hatua

1. Weka fomula ya riba changamano

2. Hesabu kipengele cha ukuaji

3. Hesabu kiasi cha mwisho

Kwa nini kujifunza hii

Vigezo na mada

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