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Ufumbuzi - Tiger algebra Suluhishaji

1256150.89

1256150.89

Tazama hatua Jifunze zaidi na Tiger Jaribu hili:

Maelezo kwa hatua

1. Weka fomula ya riba changamano

$c i (16656, 15, 12, 29)$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 16, 656$ , $r = 15 %$ , $n = 12$ , $t = 29$ .

$c i (16656, 15, 12, 29)$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 16, 656$ , $r = 15 %$ , $n = 12$ , $t = 29$ .

$P = 16656, r = 15 %, n = 12, t = 29$

$\frac{15}{100} = 0.15$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 16, 656$ , $r = 15 %$ , $n = 12$ , $t = 29$ .

$A = P {(1 + r / n)}^{(n t)}$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 16, 656$ , $r = 15 %$ , $n = 12$ , $t = 29$ .

$N e x t c o m p u t e r / n, n t, a n d {(1 + r / n)}^{(n t)} .$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 16, 656$ , $r = 15 %$ , $n = 12$ , $t = 29$ .

2. Hesabu kipengele cha ukuaji

$\frac{r}{n} = 0.0125$

$n t = 348$

${(1 + r / n)}^{(n t)}$

$r / n = 0.0125, n t = 348, {(1 + r / n)}^{(n t)} = 75.4173201991$ .

${(1 + r / n)}^{(n t)}$

${(1 + 0.0125)}^{348} = 75.4173201991$

$r / n = 0.0125, n t = 348, {(1 + r / n)}^{(n t)} = 75.4173201991$ .

$75.4173201991$

$r / n = 0.0125, n t = 348, {(1 + r / n)}^{(n t)} = 75.4173201991$ .

3. Hesabu kiasi cha mwisho

$A = 1256150.89$

$1256150.89$

$16, 656 \cdot 75.4173201991 = 1256150.89$ .

$1256150.89$

$16, 656 \cdot 75.4173201991 = 1256150.89$ .

$1256150.89$

$16, 656 \cdot 75.4173201991 = 1256150.89$ .

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Tiger algebra Suluhishaji

Ufumbuzi - Tiger algebra Suluhishaji

Maelezo kwa hatua

1. Weka fomula ya riba changamano

2. Hesabu kipengele cha ukuaji

3. Hesabu kiasi cha mwisho

Kwa nini kujifunza hii

Vigezo na mada

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