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Ufumbuzi - Tiger algebra Suluhishaji

25159.29

25159.29

Tazama hatua Jifunze zaidi na Tiger Jaribu hili:

Maelezo kwa hatua

1. Weka fomula ya riba changamano

$c i (16650, 14, 4, 3)$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 16, 650$ , $r = 14 %$ , $n = 4$ , $t = 3$ .

$c i (16650, 14, 4, 3)$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 16, 650$ , $r = 14 %$ , $n = 4$ , $t = 3$ .

$P = 16650, r = 14 %, n = 4, t = 3$

$\frac{14}{100} = 0.14$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 16, 650$ , $r = 14 %$ , $n = 4$ , $t = 3$ .

$A = P {(1 + r / n)}^{(n t)}$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 16, 650$ , $r = 14 %$ , $n = 4$ , $t = 3$ .

$N e x t c o m p u t e r / n, n t, a n d {(1 + r / n)}^{(n t)} .$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 16, 650$ , $r = 14 %$ , $n = 4$ , $t = 3$ .

2. Hesabu kipengele cha ukuaji

$\frac{r}{n} = 0.035$

$n t = 12$

${(1 + r / n)}^{(n t)}$

$r / n = 0.035, n t = 12, {(1 + r / n)}^{(n t)} = 1.5110686573$ .

${(1 + r / n)}^{(n t)}$

${(1 + 0.035)}^{12} = 1.5110686573$

$r / n = 0.035, n t = 12, {(1 + r / n)}^{(n t)} = 1.5110686573$ .

$1.5110686573$

$r / n = 0.035, n t = 12, {(1 + r / n)}^{(n t)} = 1.5110686573$ .

3. Hesabu kiasi cha mwisho

$A = 25159.29$

$25159.29$

$16, 650 \cdot 1.5110686573 = 25159.29$ .

$25159.29$

$16, 650 \cdot 1.5110686573 = 25159.29$ .

$25159.29$

$16, 650 \cdot 1.5110686573 = 25159.29$ .

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Tiger algebra Suluhishaji

Ufumbuzi - Tiger algebra Suluhishaji

Maelezo kwa hatua

1. Weka fomula ya riba changamano

2. Hesabu kipengele cha ukuaji

3. Hesabu kiasi cha mwisho

Kwa nini kujifunza hii

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