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Ufumbuzi - Tiger algebra Suluhishaji

73256.69

73256.69

Tazama hatua Jifunze zaidi na Tiger Jaribu hili:

Maelezo kwa hatua

1. Weka fomula ya riba changamano

$c i (16535, 14, 2, 11)$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 16, 535$ , $r = 14 %$ , $n = 2$ , $t = 11$ .

$c i (16535, 14, 2, 11)$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 16, 535$ , $r = 14 %$ , $n = 2$ , $t = 11$ .

$P = 16535, r = 14 %, n = 2, t = 11$

$\frac{14}{100} = 0.14$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 16, 535$ , $r = 14 %$ , $n = 2$ , $t = 11$ .

$A = P {(1 + r / n)}^{(n t)}$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 16, 535$ , $r = 14 %$ , $n = 2$ , $t = 11$ .

$N e x t c o m p u t e r / n, n t, a n d {(1 + r / n)}^{(n t)} .$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 16, 535$ , $r = 14 %$ , $n = 2$ , $t = 11$ .

2. Hesabu kipengele cha ukuaji

$\frac{r}{n} = 0.07$

$n t = 22$

${(1 + r / n)}^{(n t)}$

$r / n = 0.07, n t = 22, {(1 + r / n)}^{(n t)} = 4.4304017411$ .

${(1 + r / n)}^{(n t)}$

${(1 + 0.07)}^{22} = 4.4304017411$

$r / n = 0.07, n t = 22, {(1 + r / n)}^{(n t)} = 4.4304017411$ .

$4.4304017411$

$r / n = 0.07, n t = 22, {(1 + r / n)}^{(n t)} = 4.4304017411$ .

3. Hesabu kiasi cha mwisho

$A = 73256.69$

$73256.69$

$16, 535 \cdot 4.4304017411 = 73256.69$ .

$73256.69$

$16, 535 \cdot 4.4304017411 = 73256.69$ .

$73256.69$

$16, 535 \cdot 4.4304017411 = 73256.69$ .

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Tiger algebra Suluhishaji

Ufumbuzi - Tiger algebra Suluhishaji

Maelezo kwa hatua

1. Weka fomula ya riba changamano

2. Hesabu kipengele cha ukuaji

3. Hesabu kiasi cha mwisho

Kwa nini kujifunza hii

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