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Ufumbuzi - Tiger algebra Suluhishaji

172043.97

172043.97

Tazama hatua Jifunze zaidi na Tiger Jaribu hili:

Maelezo kwa hatua

1. Weka fomula ya riba changamano

$c i (16308, 15, 4, 16)$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 16, 308$ , $r = 15 %$ , $n = 4$ , $t = 16$ .

$c i (16308, 15, 4, 16)$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 16, 308$ , $r = 15 %$ , $n = 4$ , $t = 16$ .

$P = 16308, r = 15 %, n = 4, t = 16$

$\frac{15}{100} = 0.15$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 16, 308$ , $r = 15 %$ , $n = 4$ , $t = 16$ .

$A = P {(1 + r / n)}^{(n t)}$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 16, 308$ , $r = 15 %$ , $n = 4$ , $t = 16$ .

$N e x t c o m p u t e r / n, n t, a n d {(1 + r / n)}^{(n t)} .$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 16, 308$ , $r = 15 %$ , $n = 4$ , $t = 16$ .

2. Hesabu kipengele cha ukuaji

$\frac{r}{n} = 0.0375$

$n t = 64$

${(1 + r / n)}^{(n t)}$

$r / n = 0.0375, n t = 64, {(1 + r / n)}^{(n t)} = 10.5496668355$ .

${(1 + r / n)}^{(n t)}$

${(1 + 0.0375)}^{64} = 10.5496668355$

$r / n = 0.0375, n t = 64, {(1 + r / n)}^{(n t)} = 10.5496668355$ .

$10.5496668355$

$r / n = 0.0375, n t = 64, {(1 + r / n)}^{(n t)} = 10.5496668355$ .

3. Hesabu kiasi cha mwisho

$A = 172043.97$

$172043.97$

$16, 308 \cdot 10.5496668355 = 172043.97$ .

$172043.97$

$16, 308 \cdot 10.5496668355 = 172043.97$ .

$172043.97$

$16, 308 \cdot 10.5496668355 = 172043.97$ .

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Tiger algebra Suluhishaji

Ufumbuzi - Tiger algebra Suluhishaji

Maelezo kwa hatua

1. Weka fomula ya riba changamano

2. Hesabu kipengele cha ukuaji

3. Hesabu kiasi cha mwisho

Kwa nini kujifunza hii

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