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Ufumbuzi - Tiger algebra Suluhishaji

100650.71

100650.71

Tazama hatua Jifunze zaidi na Tiger Jaribu hili:

Maelezo kwa hatua

1. Weka fomula ya riba changamano

$c i (16278, 8, 4, 23)$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 16, 278$ , $r = 8 %$ , $n = 4$ , $t = 23$ .

$c i (16278, 8, 4, 23)$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 16, 278$ , $r = 8 %$ , $n = 4$ , $t = 23$ .

$P = 16278, r = 8 %, n = 4, t = 23$

$\frac{8}{100} = 0.08$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 16, 278$ , $r = 8 %$ , $n = 4$ , $t = 23$ .

$A = P {(1 + r / n)}^{(n t)}$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 16, 278$ , $r = 8 %$ , $n = 4$ , $t = 23$ .

$N e x t c o m p u t e r / n, n t, a n d {(1 + r / n)}^{(n t)} .$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 16, 278$ , $r = 8 %$ , $n = 4$ , $t = 23$ .

2. Hesabu kipengele cha ukuaji

$\frac{r}{n} = 0.02$

$n t = 92$

${(1 + r / n)}^{(n t)}$

$r / n = 0.02, n t = 92, {(1 + r / n)}^{(n t)} = 6.1832357046$ .

${(1 + r / n)}^{(n t)}$

${(1 + 0.02)}^{92} = 6.1832357046$

$r / n = 0.02, n t = 92, {(1 + r / n)}^{(n t)} = 6.1832357046$ .

$6.1832357046$

$r / n = 0.02, n t = 92, {(1 + r / n)}^{(n t)} = 6.1832357046$ .

3. Hesabu kiasi cha mwisho

$A = 100650.71$

$100650.71$

$16, 278 \cdot 6.1832357046 = 100650.71$ .

$100650.71$

$16, 278 \cdot 6.1832357046 = 100650.71$ .

$100650.71$

$16, 278 \cdot 6.1832357046 = 100650.71$ .

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Tiger algebra Suluhishaji

Ufumbuzi - Tiger algebra Suluhishaji

Maelezo kwa hatua

1. Weka fomula ya riba changamano

2. Hesabu kipengele cha ukuaji

3. Hesabu kiasi cha mwisho

Kwa nini kujifunza hii

Vigezo na mada

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