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Ufumbuzi - Tiger algebra Suluhishaji

72393.29

72393.29

Tazama hatua Jifunze zaidi na Tiger Jaribu hili:

Maelezo kwa hatua

1. Weka fomula ya riba changamano

$c i (16167, 11, 2, 14)$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 16, 167$ , $r = 11 %$ , $n = 2$ , $t = 14$ .

$c i (16167, 11, 2, 14)$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 16, 167$ , $r = 11 %$ , $n = 2$ , $t = 14$ .

$P = 16167, r = 11 %, n = 2, t = 14$

$\frac{11}{100} = 0.11$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 16, 167$ , $r = 11 %$ , $n = 2$ , $t = 14$ .

$A = P {(1 + r / n)}^{(n t)}$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 16, 167$ , $r = 11 %$ , $n = 2$ , $t = 14$ .

$N e x t c o m p u t e r / n, n t, a n d {(1 + r / n)}^{(n t)} .$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 16, 167$ , $r = 11 %$ , $n = 2$ , $t = 14$ .

2. Hesabu kipengele cha ukuaji

$\frac{r}{n} = 0.055$

$n t = 28$

${(1 + r / n)}^{(n t)}$

$r / n = 0.055, n t = 28, {(1 + r / n)}^{(n t)} = 4.4778430749$ .

${(1 + r / n)}^{(n t)}$

${(1 + 0.055)}^{28} = 4.4778430749$

$r / n = 0.055, n t = 28, {(1 + r / n)}^{(n t)} = 4.4778430749$ .

$4.4778430749$

$r / n = 0.055, n t = 28, {(1 + r / n)}^{(n t)} = 4.4778430749$ .

3. Hesabu kiasi cha mwisho

$A = 72393.29$

$72393.29$

$16, 167 \cdot 4.4778430749 = 72393.29$ .

$72393.29$

$16, 167 \cdot 4.4778430749 = 72393.29$ .

$72393.29$

$16, 167 \cdot 4.4778430749 = 72393.29$ .

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Jifunze zaidi na Tiger

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Tiger algebra Suluhishaji

Ufumbuzi - Tiger algebra Suluhishaji

Maelezo kwa hatua

1. Weka fomula ya riba changamano

2. Hesabu kipengele cha ukuaji

3. Hesabu kiasi cha mwisho

Kwa nini kujifunza hii

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