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Ufumbuzi - Tiger algebra Suluhishaji

39372.49

39372.49

Tazama hatua Jifunze zaidi na Tiger Jaribu hili:

Maelezo kwa hatua

1. Weka fomula ya riba changamano

$c i (16115, 6, 4, 15)$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 16, 115$ , $r = 6 %$ , $n = 4$ , $t = 15$ .

$c i (16115, 6, 4, 15)$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 16, 115$ , $r = 6 %$ , $n = 4$ , $t = 15$ .

$P = 16115, r = 6 %, n = 4, t = 15$

$\frac{6}{100} = 0.06$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 16, 115$ , $r = 6 %$ , $n = 4$ , $t = 15$ .

$A = P {(1 + r / n)}^{(n t)}$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 16, 115$ , $r = 6 %$ , $n = 4$ , $t = 15$ .

$N e x t c o m p u t e r / n, n t, a n d {(1 + r / n)}^{(n t)} .$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 16, 115$ , $r = 6 %$ , $n = 4$ , $t = 15$ .

2. Hesabu kipengele cha ukuaji

$\frac{r}{n} = 0.015$

$n t = 60$

${(1 + r / n)}^{(n t)}$

$r / n = 0.015, n t = 60, {(1 + r / n)}^{(n t)} = 2.4432197757$ .

${(1 + r / n)}^{(n t)}$

${(1 + 0.015)}^{60} = 2.4432197757$

$r / n = 0.015, n t = 60, {(1 + r / n)}^{(n t)} = 2.4432197757$ .

$2.4432197757$

$r / n = 0.015, n t = 60, {(1 + r / n)}^{(n t)} = 2.4432197757$ .

3. Hesabu kiasi cha mwisho

$A = 39372.49$

$39372.49$

$16, 115 \cdot 2.4432197757 = 39372.49$ .

$39372.49$

$16, 115 \cdot 2.4432197757 = 39372.49$ .

$39372.49$

$16, 115 \cdot 2.4432197757 = 39372.49$ .

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Jifunze zaidi na Tiger

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Tiger algebra Suluhishaji

Ufumbuzi - Tiger algebra Suluhishaji

Maelezo kwa hatua

1. Weka fomula ya riba changamano

2. Hesabu kipengele cha ukuaji

3. Hesabu kiasi cha mwisho

Kwa nini kujifunza hii

Vigezo na mada

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