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Ufumbuzi - Tiger algebra Suluhishaji

22021.64

22021.64

Tazama hatua Jifunze zaidi na Tiger Jaribu hili:

Maelezo kwa hatua

1. Weka fomula ya riba changamano

$c i (16091, 4, 1, 8)$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 16, 091$ , $r = 4 %$ , $n = 1$ , $t = 8$ .

$c i (16091, 4, 1, 8)$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 16, 091$ , $r = 4 %$ , $n = 1$ , $t = 8$ .

$P = 16091, r = 4 %, n = 1, t = 8$

$\frac{4}{100} = 0.04$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 16, 091$ , $r = 4 %$ , $n = 1$ , $t = 8$ .

$A = P {(1 + r / n)}^{(n t)}$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 16, 091$ , $r = 4 %$ , $n = 1$ , $t = 8$ .

$N e x t c o m p u t e r / n, n t, a n d {(1 + r / n)}^{(n t)} .$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 16, 091$ , $r = 4 %$ , $n = 1$ , $t = 8$ .

2. Hesabu kipengele cha ukuaji

$\frac{r}{n} = 0.04$

$n t = 8$

${(1 + r / n)}^{(n t)}$

$r / n = 0.04, n t = 8, {(1 + r / n)}^{(n t)} = 1.3685690504$ .

${(1 + r / n)}^{(n t)}$

${(1 + 0.04)}^{8} = 1.3685690504$

$r / n = 0.04, n t = 8, {(1 + r / n)}^{(n t)} = 1.3685690504$ .

$1.3685690504$

$r / n = 0.04, n t = 8, {(1 + r / n)}^{(n t)} = 1.3685690504$ .

3. Hesabu kiasi cha mwisho

$A = 22021.64$

$22021.64$

$16, 091 \cdot 1.3685690504 = 22021.64$ .

$22021.64$

$16, 091 \cdot 1.3685690504 = 22021.64$ .

$22021.64$

$16, 091 \cdot 1.3685690504 = 22021.64$ .

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Tiger algebra Suluhishaji

Ufumbuzi - Tiger algebra Suluhishaji

Maelezo kwa hatua

1. Weka fomula ya riba changamano

2. Hesabu kipengele cha ukuaji

3. Hesabu kiasi cha mwisho

Kwa nini kujifunza hii

Vigezo na mada

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