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Ufumbuzi - Tiger algebra Suluhishaji

228730.51

228730.51

Tazama hatua Jifunze zaidi na Tiger Jaribu hili:

Maelezo kwa hatua

1. Weka fomula ya riba changamano

$c i (15729, 11, 2, 25)$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 15, 729$ , $r = 11 %$ , $n = 2$ , $t = 25$ .

$c i (15729, 11, 2, 25)$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 15, 729$ , $r = 11 %$ , $n = 2$ , $t = 25$ .

$P = 15729, r = 11 %, n = 2, t = 25$

$\frac{11}{100} = 0.11$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 15, 729$ , $r = 11 %$ , $n = 2$ , $t = 25$ .

$A = P {(1 + r / n)}^{(n t)}$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 15, 729$ , $r = 11 %$ , $n = 2$ , $t = 25$ .

$N e x t c o m p u t e r / n, n t, a n d {(1 + r / n)}^{(n t)} .$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 15, 729$ , $r = 11 %$ , $n = 2$ , $t = 25$ .

2. Hesabu kipengele cha ukuaji

$\frac{r}{n} = 0.055$

$n t = 50$

${(1 + r / n)}^{(n t)}$

$r / n = 0.055, n t = 50, {(1 + r / n)}^{(n t)} = 14.5419612045$ .

${(1 + r / n)}^{(n t)}$

${(1 + 0.055)}^{50} = 14.5419612045$

$r / n = 0.055, n t = 50, {(1 + r / n)}^{(n t)} = 14.5419612045$ .

$14.5419612045$

$r / n = 0.055, n t = 50, {(1 + r / n)}^{(n t)} = 14.5419612045$ .

3. Hesabu kiasi cha mwisho

$A = 228730.51$

$228730.51$

$15, 729 \cdot 14.5419612045 = 228730.51$ .

$228730.51$

$15, 729 \cdot 14.5419612045 = 228730.51$ .

$228730.51$

$15, 729 \cdot 14.5419612045 = 228730.51$ .

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Jifunze zaidi na Tiger

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Tiger algebra Suluhishaji

Ufumbuzi - Tiger algebra Suluhishaji

Maelezo kwa hatua

1. Weka fomula ya riba changamano

2. Hesabu kipengele cha ukuaji

3. Hesabu kiasi cha mwisho

Kwa nini kujifunza hii

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