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Ufumbuzi - Tiger algebra Suluhishaji

18247.84

18247.84

Tazama hatua Jifunze zaidi na Tiger Jaribu hili:

Maelezo kwa hatua

1. Weka fomula ya riba changamano

$c i (15709, 1, 4, 15)$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 15, 709$ , $r = 1 %$ , $n = 4$ , $t = 15$ .

$c i (15709, 1, 4, 15)$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 15, 709$ , $r = 1 %$ , $n = 4$ , $t = 15$ .

$P = 15709, r = 1 %, n = 4, t = 15$

$\frac{1}{100} = 0.01$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 15, 709$ , $r = 1 %$ , $n = 4$ , $t = 15$ .

$A = P {(1 + r / n)}^{(n t)}$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 15, 709$ , $r = 1 %$ , $n = 4$ , $t = 15$ .

$N e x t c o m p u t e r / n, n t, a n d {(1 + r / n)}^{(n t)} .$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 15, 709$ , $r = 1 %$ , $n = 4$ , $t = 15$ .

2. Hesabu kipengele cha ukuaji

$\frac{r}{n} = 0.0025$

$n t = 60$

${(1 + r / n)}^{(n t)}$

$r / n = 0.0025, n t = 60, {(1 + r / n)}^{(n t)} = 1.1616167816$ .

${(1 + r / n)}^{(n t)}$

${(1 + 0.0025)}^{60} = 1.1616167816$

$r / n = 0.0025, n t = 60, {(1 + r / n)}^{(n t)} = 1.1616167816$ .

$1.1616167816$

$r / n = 0.0025, n t = 60, {(1 + r / n)}^{(n t)} = 1.1616167816$ .

3. Hesabu kiasi cha mwisho

$A = 18247.84$

$18247.84$

$15, 709 \cdot 1.1616167816 = 18247.84$ .

$18247.84$

$15, 709 \cdot 1.1616167816 = 18247.84$ .

$18247.84$

$15, 709 \cdot 1.1616167816 = 18247.84$ .

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Tiger algebra Suluhishaji

Ufumbuzi - Tiger algebra Suluhishaji

Maelezo kwa hatua

1. Weka fomula ya riba changamano

2. Hesabu kipengele cha ukuaji

3. Hesabu kiasi cha mwisho

Kwa nini kujifunza hii

Vigezo na mada

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