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Ufumbuzi - Tiger algebra Suluhishaji

92268.40

92268.40

Tazama hatua Jifunze zaidi na Tiger Jaribu hili:

Maelezo kwa hatua

1. Weka fomula ya riba changamano

$c i (15661, 6, 2, 30)$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 15, 661$ , $r = 6 %$ , $n = 2$ , $t = 30$ .

$c i (15661, 6, 2, 30)$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 15, 661$ , $r = 6 %$ , $n = 2$ , $t = 30$ .

$P = 15661, r = 6 %, n = 2, t = 30$

$\frac{6}{100} = 0.06$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 15, 661$ , $r = 6 %$ , $n = 2$ , $t = 30$ .

$A = P {(1 + r / n)}^{(n t)}$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 15, 661$ , $r = 6 %$ , $n = 2$ , $t = 30$ .

$N e x t c o m p u t e r / n, n t, a n d {(1 + r / n)}^{(n t)} .$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 15, 661$ , $r = 6 %$ , $n = 2$ , $t = 30$ .

2. Hesabu kipengele cha ukuaji

$\frac{r}{n} = 0.03$

$n t = 60$

${(1 + r / n)}^{(n t)}$

$r / n = 0.03, n t = 60, {(1 + r / n)}^{(n t)} = 5.891603104$ .

${(1 + r / n)}^{(n t)}$

${(1 + 0.03)}^{60} = 5.891603104$

$r / n = 0.03, n t = 60, {(1 + r / n)}^{(n t)} = 5.891603104$ .

$5.891603104$

$r / n = 0.03, n t = 60, {(1 + r / n)}^{(n t)} = 5.891603104$ .

3. Hesabu kiasi cha mwisho

$A = 92268.40$

$92268.40$

$15, 661 \cdot 5.891603104 = 92268.40$ .

$92268.40$

$15, 661 \cdot 5.891603104 = 92268.40$ .

$92268.40$

$15, 661 \cdot 5.891603104 = 92268.40$ .

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Jifunze zaidi na Tiger

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Tiger algebra Suluhishaji

Ufumbuzi - Tiger algebra Suluhishaji

Maelezo kwa hatua

1. Weka fomula ya riba changamano

2. Hesabu kipengele cha ukuaji

3. Hesabu kiasi cha mwisho

Kwa nini kujifunza hii

Vigezo na mada

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