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Ufumbuzi - Tiger algebra Suluhishaji

61614.00

61614.00

Tazama hatua Jifunze zaidi na Tiger Jaribu hili:

Maelezo kwa hatua

1. Weka fomula ya riba changamano

$c i (15562, 14, 4, 10)$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 15, 562$ , $r = 14 %$ , $n = 4$ , $t = 10$ .

$c i (15562, 14, 4, 10)$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 15, 562$ , $r = 14 %$ , $n = 4$ , $t = 10$ .

$P = 15562, r = 14 %, n = 4, t = 10$

$\frac{14}{100} = 0.14$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 15, 562$ , $r = 14 %$ , $n = 4$ , $t = 10$ .

$A = P {(1 + r / n)}^{(n t)}$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 15, 562$ , $r = 14 %$ , $n = 4$ , $t = 10$ .

$N e x t c o m p u t e r / n, n t, a n d {(1 + r / n)}^{(n t)} .$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 15, 562$ , $r = 14 %$ , $n = 4$ , $t = 10$ .

2. Hesabu kipengele cha ukuaji

$\frac{r}{n} = 0.035$

$n t = 40$

${(1 + r / n)}^{(n t)}$

$r / n = 0.035, n t = 40, {(1 + r / n)}^{(n t)} = 3.9592597212$ .

${(1 + r / n)}^{(n t)}$

${(1 + 0.035)}^{40} = 3.9592597212$

$r / n = 0.035, n t = 40, {(1 + r / n)}^{(n t)} = 3.9592597212$ .

$3.9592597212$

$r / n = 0.035, n t = 40, {(1 + r / n)}^{(n t)} = 3.9592597212$ .

3. Hesabu kiasi cha mwisho

$A = 61614.00$

$61614.00$

$15, 562 \cdot 3.9592597212 = 61614.00$ .

$61614.00$

$15, 562 \cdot 3.9592597212 = 61614.00$ .

$61614.00$

$15, 562 \cdot 3.9592597212 = 61614.00$ .

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Jifunze zaidi na Tiger

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Tiger algebra Suluhishaji

Ufumbuzi - Tiger algebra Suluhishaji

Maelezo kwa hatua

1. Weka fomula ya riba changamano

2. Hesabu kipengele cha ukuaji

3. Hesabu kiasi cha mwisho

Kwa nini kujifunza hii

Vigezo na mada

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