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Ufumbuzi - Tiger algebra Suluhishaji

28901.54

28901.54

Tazama hatua Jifunze zaidi na Tiger Jaribu hili:

Maelezo kwa hatua

1. Weka fomula ya riba changamano

$c i (15536, 3, 1, 21)$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 15, 536$ , $r = 3 %$ , $n = 1$ , $t = 21$ .

$c i (15536, 3, 1, 21)$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 15, 536$ , $r = 3 %$ , $n = 1$ , $t = 21$ .

$P = 15536, r = 3 %, n = 1, t = 21$

$\frac{3}{100} = 0.03$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 15, 536$ , $r = 3 %$ , $n = 1$ , $t = 21$ .

$A = P {(1 + r / n)}^{(n t)}$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 15, 536$ , $r = 3 %$ , $n = 1$ , $t = 21$ .

$N e x t c o m p u t e r / n, n t, a n d {(1 + r / n)}^{(n t)} .$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 15, 536$ , $r = 3 %$ , $n = 1$ , $t = 21$ .

2. Hesabu kipengele cha ukuaji

$\frac{r}{n} = 0.03$

$n t = 21$

${(1 + r / n)}^{(n t)}$

$r / n = 0.03, n t = 21, {(1 + r / n)}^{(n t)} = 1.8602945717$ .

${(1 + r / n)}^{(n t)}$

${(1 + 0.03)}^{21} = 1.8602945717$

$r / n = 0.03, n t = 21, {(1 + r / n)}^{(n t)} = 1.8602945717$ .

$1.8602945717$

$r / n = 0.03, n t = 21, {(1 + r / n)}^{(n t)} = 1.8602945717$ .

3. Hesabu kiasi cha mwisho

$A = 28901.54$

$28901.54$

$15, 536 \cdot 1.8602945717 = 28901.54$ .

$28901.54$

$15, 536 \cdot 1.8602945717 = 28901.54$ .

$28901.54$

$15, 536 \cdot 1.8602945717 = 28901.54$ .

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Jifunze zaidi na Tiger

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Tiger algebra Suluhishaji

Ufumbuzi - Tiger algebra Suluhishaji

Maelezo kwa hatua

1. Weka fomula ya riba changamano

2. Hesabu kipengele cha ukuaji

3. Hesabu kiasi cha mwisho

Kwa nini kujifunza hii

Vigezo na mada

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