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Ufumbuzi - Tiger algebra Suluhishaji

94735.43

94735.43

Tazama hatua Jifunze zaidi na Tiger Jaribu hili:

Maelezo kwa hatua

1. Weka fomula ya riba changamano

$c i (15490, 10, 1, 19)$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 15, 490$ , $r = 10 %$ , $n = 1$ , $t = 19$ .

$c i (15490, 10, 1, 19)$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 15, 490$ , $r = 10 %$ , $n = 1$ , $t = 19$ .

$P = 15490, r = 10 %, n = 1, t = 19$

$\frac{10}{100} = 0.1$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 15, 490$ , $r = 10 %$ , $n = 1$ , $t = 19$ .

$A = P {(1 + r / n)}^{(n t)}$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 15, 490$ , $r = 10 %$ , $n = 1$ , $t = 19$ .

$N e x t c o m p u t e r / n, n t, a n d {(1 + r / n)}^{(n t)} .$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 15, 490$ , $r = 10 %$ , $n = 1$ , $t = 19$ .

2. Hesabu kipengele cha ukuaji

$\frac{r}{n} = 0.1$

$n t = 19$

${(1 + r / n)}^{(n t)}$

$r / n = 0.1, n t = 19, {(1 + r / n)}^{(n t)} = 6.1159090448$ .

${(1 + r / n)}^{(n t)}$

${(1 + 0.1)}^{19} = 6.1159090448$

$r / n = 0.1, n t = 19, {(1 + r / n)}^{(n t)} = 6.1159090448$ .

$6.1159090448$

$r / n = 0.1, n t = 19, {(1 + r / n)}^{(n t)} = 6.1159090448$ .

3. Hesabu kiasi cha mwisho

$A = 94735.43$

$94735.43$

$15, 490 \cdot 6.1159090448 = 94735.43$ .

$94735.43$

$15, 490 \cdot 6.1159090448 = 94735.43$ .

$94735.43$

$15, 490 \cdot 6.1159090448 = 94735.43$ .

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Jifunze zaidi na Tiger

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Tiger algebra Suluhishaji

Ufumbuzi - Tiger algebra Suluhishaji

Maelezo kwa hatua

1. Weka fomula ya riba changamano

2. Hesabu kipengele cha ukuaji

3. Hesabu kiasi cha mwisho

Kwa nini kujifunza hii

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