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Ufumbuzi - Tiger algebra Suluhishaji

25621.70

25621.70

Tazama hatua Jifunze zaidi na Tiger Jaribu hili:

Maelezo kwa hatua

1. Weka fomula ya riba changamano

$c i (15311, 4, 2, 13)$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 15, 311$ , $r = 4 %$ , $n = 2$ , $t = 13$ .

$c i (15311, 4, 2, 13)$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 15, 311$ , $r = 4 %$ , $n = 2$ , $t = 13$ .

$P = 15311, r = 4 %, n = 2, t = 13$

$\frac{4}{100} = 0.04$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 15, 311$ , $r = 4 %$ , $n = 2$ , $t = 13$ .

$A = P {(1 + r / n)}^{(n t)}$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 15, 311$ , $r = 4 %$ , $n = 2$ , $t = 13$ .

$N e x t c o m p u t e r / n, n t, a n d {(1 + r / n)}^{(n t)} .$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 15, 311$ , $r = 4 %$ , $n = 2$ , $t = 13$ .

2. Hesabu kipengele cha ukuaji

$\frac{r}{n} = 0.02$

$n t = 26$

${(1 + r / n)}^{(n t)}$

$r / n = 0.02, n t = 26, {(1 + r / n)}^{(n t)} = 1.6734181144$ .

${(1 + r / n)}^{(n t)}$

${(1 + 0.02)}^{26} = 1.6734181144$

$r / n = 0.02, n t = 26, {(1 + r / n)}^{(n t)} = 1.6734181144$ .

$1.6734181144$

$r / n = 0.02, n t = 26, {(1 + r / n)}^{(n t)} = 1.6734181144$ .

3. Hesabu kiasi cha mwisho

$A = 25621.70$

$25621.70$

$15, 311 \cdot 1.6734181144 = 25621.70$ .

$25621.70$

$15, 311 \cdot 1.6734181144 = 25621.70$ .

$25621.70$

$15, 311 \cdot 1.6734181144 = 25621.70$ .

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Jifunze zaidi na Tiger

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Tiger algebra Suluhishaji

Ufumbuzi - Tiger algebra Suluhishaji

Maelezo kwa hatua

1. Weka fomula ya riba changamano

2. Hesabu kipengele cha ukuaji

3. Hesabu kiasi cha mwisho

Kwa nini kujifunza hii

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