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Ufumbuzi - Tiger algebra Suluhishaji

268652.14

268652.14

Tazama hatua Jifunze zaidi na Tiger Jaribu hili:

Maelezo kwa hatua

1. Weka fomula ya riba changamano

$c i (15298, 12, 12, 24)$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 15, 298$ , $r = 12 %$ , $n = 12$ , $t = 24$ .

$c i (15298, 12, 12, 24)$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 15, 298$ , $r = 12 %$ , $n = 12$ , $t = 24$ .

$P = 15298, r = 12 %, n = 12, t = 24$

$\frac{12}{100} = 0.12$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 15, 298$ , $r = 12 %$ , $n = 12$ , $t = 24$ .

$A = P {(1 + r / n)}^{(n t)}$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 15, 298$ , $r = 12 %$ , $n = 12$ , $t = 24$ .

$N e x t c o m p u t e r / n, n t, a n d {(1 + r / n)}^{(n t)} .$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 15, 298$ , $r = 12 %$ , $n = 12$ , $t = 24$ .

2. Hesabu kipengele cha ukuaji

$\frac{r}{n} = 0.01$

$n t = 288$

${(1 + r / n)}^{(n t)}$

$r / n = 0.01, n t = 288, {(1 + r / n)}^{(n t)} = 17.5612590533$ .

${(1 + r / n)}^{(n t)}$

${(1 + 0.01)}^{288} = 17.5612590533$

$r / n = 0.01, n t = 288, {(1 + r / n)}^{(n t)} = 17.5612590533$ .

$17.5612590533$

$r / n = 0.01, n t = 288, {(1 + r / n)}^{(n t)} = 17.5612590533$ .

3. Hesabu kiasi cha mwisho

$A = 268652.14$

$268652.14$

$15, 298 \cdot 17.5612590533 = 268652.14$ .

$268652.14$

$15, 298 \cdot 17.5612590533 = 268652.14$ .

$268652.14$

$15, 298 \cdot 17.5612590533 = 268652.14$ .

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Tiger algebra Suluhishaji

Ufumbuzi - Tiger algebra Suluhishaji

Maelezo kwa hatua

1. Weka fomula ya riba changamano

2. Hesabu kipengele cha ukuaji

3. Hesabu kiasi cha mwisho

Kwa nini kujifunza hii

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