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Ufumbuzi - Tiger algebra Suluhishaji

280704.73

280704.73

Tazama hatua Jifunze zaidi na Tiger Jaribu hili:

Maelezo kwa hatua

1. Weka fomula ya riba changamano

$c i (15239, 12, 2, 25)$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 15, 239$ , $r = 12 %$ , $n = 2$ , $t = 25$ .

$c i (15239, 12, 2, 25)$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 15, 239$ , $r = 12 %$ , $n = 2$ , $t = 25$ .

$P = 15239, r = 12 %, n = 2, t = 25$

$\frac{12}{100} = 0.12$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 15, 239$ , $r = 12 %$ , $n = 2$ , $t = 25$ .

$A = P {(1 + r / n)}^{(n t)}$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 15, 239$ , $r = 12 %$ , $n = 2$ , $t = 25$ .

$N e x t c o m p u t e r / n, n t, a n d {(1 + r / n)}^{(n t)} .$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 15, 239$ , $r = 12 %$ , $n = 2$ , $t = 25$ .

2. Hesabu kipengele cha ukuaji

$\frac{r}{n} = 0.06$

$n t = 50$

${(1 + r / n)}^{(n t)}$

$r / n = 0.06, n t = 50, {(1 + r / n)}^{(n t)} = 18.420154275$ .

${(1 + r / n)}^{(n t)}$

${(1 + 0.06)}^{50} = 18.420154275$

$r / n = 0.06, n t = 50, {(1 + r / n)}^{(n t)} = 18.420154275$ .

$18.420154275$

$r / n = 0.06, n t = 50, {(1 + r / n)}^{(n t)} = 18.420154275$ .

3. Hesabu kiasi cha mwisho

$A = 280704.73$

$280704.73$

$15, 239 \cdot 18.420154275 = 280704.73$ .

$280704.73$

$15, 239 \cdot 18.420154275 = 280704.73$ .

$280704.73$

$15, 239 \cdot 18.420154275 = 280704.73$ .

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Jifunze zaidi na Tiger

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Tiger algebra Suluhishaji

Ufumbuzi - Tiger algebra Suluhishaji

Maelezo kwa hatua

1. Weka fomula ya riba changamano

2. Hesabu kipengele cha ukuaji

3. Hesabu kiasi cha mwisho

Kwa nini kujifunza hii

Vigezo na mada

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