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Ufumbuzi - Tiger algebra Suluhishaji

27112.43

27112.43

Tazama hatua Jifunze zaidi na Tiger Jaribu hili:

Maelezo kwa hatua

1. Weka fomula ya riba changamano

$c i (15224, 2, 2, 29)$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 15, 224$ , $r = 2 %$ , $n = 2$ , $t = 29$ .

$c i (15224, 2, 2, 29)$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 15, 224$ , $r = 2 %$ , $n = 2$ , $t = 29$ .

$P = 15224, r = 2 %, n = 2, t = 29$

$\frac{2}{100} = 0.02$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 15, 224$ , $r = 2 %$ , $n = 2$ , $t = 29$ .

$A = P {(1 + r / n)}^{(n t)}$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 15, 224$ , $r = 2 %$ , $n = 2$ , $t = 29$ .

$N e x t c o m p u t e r / n, n t, a n d {(1 + r / n)}^{(n t)} .$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 15, 224$ , $r = 2 %$ , $n = 2$ , $t = 29$ .

2. Hesabu kipengele cha ukuaji

$\frac{r}{n} = 0.01$

$n t = 58$

${(1 + r / n)}^{(n t)}$

$r / n = 0.01, n t = 58, {(1 + r / n)}^{(n t)} = 1.7809005966$ .

${(1 + r / n)}^{(n t)}$

${(1 + 0.01)}^{58} = 1.7809005966$

$r / n = 0.01, n t = 58, {(1 + r / n)}^{(n t)} = 1.7809005966$ .

$1.7809005966$

$r / n = 0.01, n t = 58, {(1 + r / n)}^{(n t)} = 1.7809005966$ .

3. Hesabu kiasi cha mwisho

$A = 27112.43$

$27112.43$

$15, 224 \cdot 1.7809005966 = 27112.43$ .

$27112.43$

$15, 224 \cdot 1.7809005966 = 27112.43$ .

$27112.43$

$15, 224 \cdot 1.7809005966 = 27112.43$ .

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Tiger algebra Suluhishaji

Ufumbuzi - Tiger algebra Suluhishaji

Maelezo kwa hatua

1. Weka fomula ya riba changamano

2. Hesabu kipengele cha ukuaji

3. Hesabu kiasi cha mwisho

Kwa nini kujifunza hii

Vigezo na mada

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