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Ufumbuzi - Tiger algebra Suluhishaji

39563.17

39563.17

Tazama hatua Jifunze zaidi na Tiger Jaribu hili:

Maelezo kwa hatua

1. Weka fomula ya riba changamano

$c i (15092, 11, 2, 9)$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 15, 092$ , $r = 11 %$ , $n = 2$ , $t = 9$ .

$c i (15092, 11, 2, 9)$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 15, 092$ , $r = 11 %$ , $n = 2$ , $t = 9$ .

$P = 15092, r = 11 %, n = 2, t = 9$

$\frac{11}{100} = 0.11$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 15, 092$ , $r = 11 %$ , $n = 2$ , $t = 9$ .

$A = P {(1 + r / n)}^{(n t)}$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 15, 092$ , $r = 11 %$ , $n = 2$ , $t = 9$ .

$N e x t c o m p u t e r / n, n t, a n d {(1 + r / n)}^{(n t)} .$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 15, 092$ , $r = 11 %$ , $n = 2$ , $t = 9$ .

2. Hesabu kipengele cha ukuaji

$\frac{r}{n} = 0.055$

$n t = 18$

${(1 + r / n)}^{(n t)}$

$r / n = 0.055, n t = 18, {(1 + r / n)}^{(n t)} = 2.6214662659$ .

${(1 + r / n)}^{(n t)}$

${(1 + 0.055)}^{18} = 2.6214662659$

$r / n = 0.055, n t = 18, {(1 + r / n)}^{(n t)} = 2.6214662659$ .

$2.6214662659$

$r / n = 0.055, n t = 18, {(1 + r / n)}^{(n t)} = 2.6214662659$ .

3. Hesabu kiasi cha mwisho

$A = 39563.17$

$39563.17$

$15, 092 \cdot 2.6214662659 = 39563.17$ .

$39563.17$

$15, 092 \cdot 2.6214662659 = 39563.17$ .

$39563.17$

$15, 092 \cdot 2.6214662659 = 39563.17$ .

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Tiger algebra Suluhishaji

Ufumbuzi - Tiger algebra Suluhishaji

Maelezo kwa hatua

1. Weka fomula ya riba changamano

2. Hesabu kipengele cha ukuaji

3. Hesabu kiasi cha mwisho

Kwa nini kujifunza hii

Vigezo na mada

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