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Ufumbuzi - Tiger algebra Suluhishaji

16093.85

16093.85

Tazama hatua Jifunze zaidi na Tiger Jaribu hili:

Maelezo kwa hatua

1. Weka fomula ya riba changamano

$c i (14765, 9, 1, 1)$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 14, 765$ , $r = 9 %$ , $n = 1$ , $t = 1$ .

$c i (14765, 9, 1, 1)$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 14, 765$ , $r = 9 %$ , $n = 1$ , $t = 1$ .

$P = 14765, r = 9 %, n = 1, t = 1$

$\frac{9}{100} = 0.09$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 14, 765$ , $r = 9 %$ , $n = 1$ , $t = 1$ .

$A = P {(1 + r / n)}^{(n t)}$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 14, 765$ , $r = 9 %$ , $n = 1$ , $t = 1$ .

$N e x t c o m p u t e r / n, n t, a n d {(1 + r / n)}^{(n t)} .$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 14, 765$ , $r = 9 %$ , $n = 1$ , $t = 1$ .

2. Hesabu kipengele cha ukuaji

$\frac{r}{n} = 0.09$

$n t = 1$

${(1 + r / n)}^{(n t)}$

$r / n = 0.09, n t = 1, {(1 + r / n)}^{(n t)} = 1.09$ .

${(1 + r / n)}^{(n t)}$

${(1 + 0.09)}^{1} = 1.09$

$r / n = 0.09, n t = 1, {(1 + r / n)}^{(n t)} = 1.09$ .

$1.09$

$r / n = 0.09, n t = 1, {(1 + r / n)}^{(n t)} = 1.09$ .

3. Hesabu kiasi cha mwisho

$A = 16093.85$

$16093.85$

$14, 765 \cdot 1.09 = 16093.85$ .

$16093.85$

$14, 765 \cdot 1.09 = 16093.85$ .

$16093.85$

$14, 765 \cdot 1.09 = 16093.85$ .

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Tiger algebra Suluhishaji

Ufumbuzi - Tiger algebra Suluhishaji

Maelezo kwa hatua

1. Weka fomula ya riba changamano

2. Hesabu kipengele cha ukuaji

3. Hesabu kiasi cha mwisho

Kwa nini kujifunza hii

Vigezo na mada

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