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Ufumbuzi - Tiger algebra Suluhishaji

4119.28

4119.28

Tazama hatua Jifunze zaidi na Tiger Jaribu hili:

Maelezo kwa hatua

1. Weka fomula ya riba changamano

$c i (1471, 4, 2, 26)$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 1, 471$ , $r = 4 %$ , $n = 2$ , $t = 26$ .

$c i (1471, 4, 2, 26)$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 1, 471$ , $r = 4 %$ , $n = 2$ , $t = 26$ .

$P = 1471, r = 4 %, n = 2, t = 26$

$\frac{4}{100} = 0.04$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 1, 471$ , $r = 4 %$ , $n = 2$ , $t = 26$ .

$A = P {(1 + r / n)}^{(n t)}$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 1, 471$ , $r = 4 %$ , $n = 2$ , $t = 26$ .

$N e x t c o m p u t e r / n, n t, a n d {(1 + r / n)}^{(n t)} .$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 1, 471$ , $r = 4 %$ , $n = 2$ , $t = 26$ .

2. Hesabu kipengele cha ukuaji

$\frac{r}{n} = 0.02$

$n t = 52$

${(1 + r / n)}^{(n t)}$

$r / n = 0.02, n t = 52, {(1 + r / n)}^{(n t)} = 2.8003281854$ .

${(1 + r / n)}^{(n t)}$

${(1 + 0.02)}^{52} = 2.8003281854$

$r / n = 0.02, n t = 52, {(1 + r / n)}^{(n t)} = 2.8003281854$ .

$2.8003281854$

$r / n = 0.02, n t = 52, {(1 + r / n)}^{(n t)} = 2.8003281854$ .

3. Hesabu kiasi cha mwisho

$A = 4119.28$

$4119.28$

$1, 471 \cdot 2.8003281854 = 4119.28$ .

$4119.28$

$1, 471 \cdot 2.8003281854 = 4119.28$ .

$4119.28$

$1, 471 \cdot 2.8003281854 = 4119.28$ .

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Jifunze zaidi na Tiger

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Tiger algebra Suluhishaji

Ufumbuzi - Tiger algebra Suluhishaji

Maelezo kwa hatua

1. Weka fomula ya riba changamano

2. Hesabu kipengele cha ukuaji

3. Hesabu kiasi cha mwisho

Kwa nini kujifunza hii

Vigezo na mada

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