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Ufumbuzi - Tiger algebra Suluhishaji

16795.63

16795.63

Tazama hatua Jifunze zaidi na Tiger Jaribu hili:

Maelezo kwa hatua

1. Weka fomula ya riba changamano

$c i (14318, 2, 4, 8)$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 14, 318$ , $r = 2 %$ , $n = 4$ , $t = 8$ .

$c i (14318, 2, 4, 8)$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 14, 318$ , $r = 2 %$ , $n = 4$ , $t = 8$ .

$P = 14318, r = 2 %, n = 4, t = 8$

$\frac{2}{100} = 0.02$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 14, 318$ , $r = 2 %$ , $n = 4$ , $t = 8$ .

$A = P {(1 + r / n)}^{(n t)}$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 14, 318$ , $r = 2 %$ , $n = 4$ , $t = 8$ .

$N e x t c o m p u t e r / n, n t, a n d {(1 + r / n)}^{(n t)} .$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 14, 318$ , $r = 2 %$ , $n = 4$ , $t = 8$ .

2. Hesabu kipengele cha ukuaji

$\frac{r}{n} = 0.005$

$n t = 32$

${(1 + r / n)}^{(n t)}$

$r / n = 0.005, n t = 32, {(1 + r / n)}^{(n t)} = 1.1730431187$ .

${(1 + r / n)}^{(n t)}$

${(1 + 0.005)}^{32} = 1.1730431187$

$r / n = 0.005, n t = 32, {(1 + r / n)}^{(n t)} = 1.1730431187$ .

$1.1730431187$

$r / n = 0.005, n t = 32, {(1 + r / n)}^{(n t)} = 1.1730431187$ .

3. Hesabu kiasi cha mwisho

$A = 16795.63$

$16795.63$

$14, 318 \cdot 1.1730431187 = 16795.63$ .

$16795.63$

$14, 318 \cdot 1.1730431187 = 16795.63$ .

$16795.63$

$14, 318 \cdot 1.1730431187 = 16795.63$ .

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Tiger algebra Suluhishaji

Ufumbuzi - Tiger algebra Suluhishaji

Maelezo kwa hatua

1. Weka fomula ya riba changamano

2. Hesabu kipengele cha ukuaji

3. Hesabu kiasi cha mwisho

Kwa nini kujifunza hii

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