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Ufumbuzi - Tiger algebra Suluhishaji

6991.65

6991.65

Tazama hatua Jifunze zaidi na Tiger Jaribu hili:

Maelezo kwa hatua

1. Weka fomula ya riba changamano

$c i (1417, 6, 2, 27)$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 1, 417$ , $r = 6 %$ , $n = 2$ , $t = 27$ .

$c i (1417, 6, 2, 27)$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 1, 417$ , $r = 6 %$ , $n = 2$ , $t = 27$ .

$P = 1417, r = 6 %, n = 2, t = 27$

$\frac{6}{100} = 0.06$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 1, 417$ , $r = 6 %$ , $n = 2$ , $t = 27$ .

$A = P {(1 + r / n)}^{(n t)}$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 1, 417$ , $r = 6 %$ , $n = 2$ , $t = 27$ .

$N e x t c o m p u t e r / n, n t, a n d {(1 + r / n)}^{(n t)} .$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 1, 417$ , $r = 6 %$ , $n = 2$ , $t = 27$ .

2. Hesabu kipengele cha ukuaji

$\frac{r}{n} = 0.03$

$n t = 54$

${(1 + r / n)}^{(n t)}$

$r / n = 0.03, n t = 54, {(1 + r / n)}^{(n t)} = 4.9341248463$ .

${(1 + r / n)}^{(n t)}$

${(1 + 0.03)}^{54} = 4.9341248463$

$r / n = 0.03, n t = 54, {(1 + r / n)}^{(n t)} = 4.9341248463$ .

$4.9341248463$

$r / n = 0.03, n t = 54, {(1 + r / n)}^{(n t)} = 4.9341248463$ .

3. Hesabu kiasi cha mwisho

$A = 6991.65$

$6991.65$

$1, 417 \cdot 4.9341248463 = 6991.65$ .

$6991.65$

$1, 417 \cdot 4.9341248463 = 6991.65$ .

$6991.65$

$1, 417 \cdot 4.9341248463 = 6991.65$ .

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Tiger algebra Suluhishaji

Ufumbuzi - Tiger algebra Suluhishaji

Maelezo kwa hatua

1. Weka fomula ya riba changamano

2. Hesabu kipengele cha ukuaji

3. Hesabu kiasi cha mwisho

Kwa nini kujifunza hii

Vigezo na mada

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