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Ufumbuzi - Tiger algebra Suluhishaji

1000150.28

1000150.28

Tazama hatua Jifunze zaidi na Tiger Jaribu hili:

Maelezo kwa hatua

1. Weka fomula ya riba changamano

$c i (13978, 15, 4, 29)$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 13, 978$ , $r = 15 %$ , $n = 4$ , $t = 29$ .

$c i (13978, 15, 4, 29)$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 13, 978$ , $r = 15 %$ , $n = 4$ , $t = 29$ .

$P = 13978, r = 15 %, n = 4, t = 29$

$\frac{15}{100} = 0.15$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 13, 978$ , $r = 15 %$ , $n = 4$ , $t = 29$ .

$A = P {(1 + r / n)}^{(n t)}$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 13, 978$ , $r = 15 %$ , $n = 4$ , $t = 29$ .

$N e x t c o m p u t e r / n, n t, a n d {(1 + r / n)}^{(n t)} .$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 13, 978$ , $r = 15 %$ , $n = 4$ , $t = 29$ .

2. Hesabu kipengele cha ukuaji

$\frac{r}{n} = 0.0375$

$n t = 116$

${(1 + r / n)}^{(n t)}$

$r / n = 0.0375, n t = 116, {(1 + r / n)}^{(n t)} = 71.5517441407$ .

${(1 + r / n)}^{(n t)}$

${(1 + 0.0375)}^{116} = 71.5517441407$

$r / n = 0.0375, n t = 116, {(1 + r / n)}^{(n t)} = 71.5517441407$ .

$71.5517441407$

$r / n = 0.0375, n t = 116, {(1 + r / n)}^{(n t)} = 71.5517441407$ .

3. Hesabu kiasi cha mwisho

$A = 1000150.28$

$1000150.28$

$13, 978 \cdot 71.5517441407 = 1000150.28$ .

$1000150.28$

$13, 978 \cdot 71.5517441407 = 1000150.28$ .

$1000150.28$

$13, 978 \cdot 71.5517441407 = 1000150.28$ .

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Tiger algebra Suluhishaji

Ufumbuzi - Tiger algebra Suluhishaji

Maelezo kwa hatua

1. Weka fomula ya riba changamano

2. Hesabu kipengele cha ukuaji

3. Hesabu kiasi cha mwisho

Kwa nini kujifunza hii

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