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Ufumbuzi - Tiger algebra Suluhishaji

208421.46

208421.46

Tazama hatua Jifunze zaidi na Tiger Jaribu hili:

Maelezo kwa hatua

1. Weka fomula ya riba changamano

$c i (13828, 11, 4, 25)$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 13, 828$ , $r = 11 %$ , $n = 4$ , $t = 25$ .

$c i (13828, 11, 4, 25)$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 13, 828$ , $r = 11 %$ , $n = 4$ , $t = 25$ .

$P = 13828, r = 11 %, n = 4, t = 25$

$\frac{11}{100} = 0.11$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 13, 828$ , $r = 11 %$ , $n = 4$ , $t = 25$ .

$A = P {(1 + r / n)}^{(n t)}$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 13, 828$ , $r = 11 %$ , $n = 4$ , $t = 25$ .

$N e x t c o m p u t e r / n, n t, a n d {(1 + r / n)}^{(n t)} .$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 13, 828$ , $r = 11 %$ , $n = 4$ , $t = 25$ .

2. Hesabu kipengele cha ukuaji

$\frac{r}{n} = 0.0275$

$n t = 100$

${(1 + r / n)}^{(n t)}$

$r / n = 0.0275, n t = 100, {(1 + r / n)}^{(n t)} = 15.0724223383$ .

${(1 + r / n)}^{(n t)}$

${(1 + 0.0275)}^{100} = 15.0724223383$

$r / n = 0.0275, n t = 100, {(1 + r / n)}^{(n t)} = 15.0724223383$ .

$15.0724223383$

$r / n = 0.0275, n t = 100, {(1 + r / n)}^{(n t)} = 15.0724223383$ .

3. Hesabu kiasi cha mwisho

$A = 208421.46$

$208421.46$

$13, 828 \cdot 15.0724223383 = 208421.46$ .

$208421.46$

$13, 828 \cdot 15.0724223383 = 208421.46$ .

$208421.46$

$13, 828 \cdot 15.0724223383 = 208421.46$ .

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Tiger algebra Suluhishaji

Ufumbuzi - Tiger algebra Suluhishaji

Maelezo kwa hatua

1. Weka fomula ya riba changamano

2. Hesabu kipengele cha ukuaji

3. Hesabu kiasi cha mwisho

Kwa nini kujifunza hii

Vigezo na mada

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