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Ufumbuzi - Tiger algebra Suluhishaji

98203.51

98203.51

Tazama hatua Jifunze zaidi na Tiger Jaribu hili:

Maelezo kwa hatua

1. Weka fomula ya riba changamano

$c i (13401, 10, 12, 20)$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 13, 401$ , $r = 10 %$ , $n = 12$ , $t = 20$ .

$c i (13401, 10, 12, 20)$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 13, 401$ , $r = 10 %$ , $n = 12$ , $t = 20$ .

$P = 13401, r = 10 %, n = 12, t = 20$

$\frac{10}{100} = 0.1$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 13, 401$ , $r = 10 %$ , $n = 12$ , $t = 20$ .

$A = P {(1 + r / n)}^{(n t)}$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 13, 401$ , $r = 10 %$ , $n = 12$ , $t = 20$ .

$N e x t c o m p u t e r / n, n t, a n d {(1 + r / n)}^{(n t)} .$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 13, 401$ , $r = 10 %$ , $n = 12$ , $t = 20$ .

2. Hesabu kipengele cha ukuaji

$\frac{r}{n} = 0.0083333333$

$n t = 240$

${(1 + r / n)}^{(n t)}$

$r / n = 0.0083333333, n t = 240, {(1 + r / n)}^{(n t)} = 7.3280736332$ .

${(1 + r / n)}^{(n t)}$

${(1 + 0.0083333333)}^{240} = 7.3280736332$

$r / n = 0.0083333333, n t = 240, {(1 + r / n)}^{(n t)} = 7.3280736332$ .

$7.3280736332$

$r / n = 0.0083333333, n t = 240, {(1 + r / n)}^{(n t)} = 7.3280736332$ .

3. Hesabu kiasi cha mwisho

$A = 98203.51$

$98203.51$

$13, 401 \cdot 7.3280736332 = 98203.51$ .

$98203.51$

$13, 401 \cdot 7.3280736332 = 98203.51$ .

$98203.51$

$13, 401 \cdot 7.3280736332 = 98203.51$ .

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Tiger algebra Suluhishaji

Ufumbuzi - Tiger algebra Suluhishaji

Maelezo kwa hatua

1. Weka fomula ya riba changamano

2. Hesabu kipengele cha ukuaji

3. Hesabu kiasi cha mwisho

Kwa nini kujifunza hii

Vigezo na mada

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