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Ufumbuzi - Tiger algebra Suluhishaji

289202.99

289202.99

Tazama hatua Jifunze zaidi na Tiger Jaribu hili:

Maelezo kwa hatua

1. Weka fomula ya riba changamano

$c i (13370, 12, 4, 26)$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 13, 370$ , $r = 12 %$ , $n = 4$ , $t = 26$ .

$c i (13370, 12, 4, 26)$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 13, 370$ , $r = 12 %$ , $n = 4$ , $t = 26$ .

$P = 13370, r = 12 %, n = 4, t = 26$

$\frac{12}{100} = 0.12$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 13, 370$ , $r = 12 %$ , $n = 4$ , $t = 26$ .

$A = P {(1 + r / n)}^{(n t)}$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 13, 370$ , $r = 12 %$ , $n = 4$ , $t = 26$ .

$N e x t c o m p u t e r / n, n t, a n d {(1 + r / n)}^{(n t)} .$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 13, 370$ , $r = 12 %$ , $n = 4$ , $t = 26$ .

2. Hesabu kipengele cha ukuaji

$\frac{r}{n} = 0.03$

$n t = 104$

${(1 + r / n)}^{(n t)}$

$r / n = 0.03, n t = 104, {(1 + r / n)}^{(n t)} = 21.6307396106$ .

${(1 + r / n)}^{(n t)}$

${(1 + 0.03)}^{104} = 21.6307396106$

$r / n = 0.03, n t = 104, {(1 + r / n)}^{(n t)} = 21.6307396106$ .

$21.6307396106$

$r / n = 0.03, n t = 104, {(1 + r / n)}^{(n t)} = 21.6307396106$ .

3. Hesabu kiasi cha mwisho

$A = 289202.99$

$289202.99$

$13, 370 \cdot 21.6307396106 = 289202.99$ .

$289202.99$

$13, 370 \cdot 21.6307396106 = 289202.99$ .

$289202.99$

$13, 370 \cdot 21.6307396106 = 289202.99$ .

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Jifunze zaidi na Tiger

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Tiger algebra Suluhishaji

Ufumbuzi - Tiger algebra Suluhishaji

Maelezo kwa hatua

1. Weka fomula ya riba changamano

2. Hesabu kipengele cha ukuaji

3. Hesabu kiasi cha mwisho

Kwa nini kujifunza hii

Vigezo na mada

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