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Ufumbuzi - Tiger algebra Suluhishaji

26133.61

26133.61

Tazama hatua Jifunze zaidi na Tiger Jaribu hili:

Maelezo kwa hatua

1. Weka fomula ya riba changamano

$c i (13285, 14, 2, 5)$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 13, 285$ , $r = 14 %$ , $n = 2$ , $t = 5$ .

$c i (13285, 14, 2, 5)$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 13, 285$ , $r = 14 %$ , $n = 2$ , $t = 5$ .

$P = 13285, r = 14 %, n = 2, t = 5$

$\frac{14}{100} = 0.14$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 13, 285$ , $r = 14 %$ , $n = 2$ , $t = 5$ .

$A = P {(1 + r / n)}^{(n t)}$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 13, 285$ , $r = 14 %$ , $n = 2$ , $t = 5$ .

$N e x t c o m p u t e r / n, n t, a n d {(1 + r / n)}^{(n t)} .$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 13, 285$ , $r = 14 %$ , $n = 2$ , $t = 5$ .

2. Hesabu kipengele cha ukuaji

$\frac{r}{n} = 0.07$

$n t = 10$

${(1 + r / n)}^{(n t)}$

$r / n = 0.07, n t = 10, {(1 + r / n)}^{(n t)} = 1.9671513573$ .

${(1 + r / n)}^{(n t)}$

${(1 + 0.07)}^{10} = 1.9671513573$

$r / n = 0.07, n t = 10, {(1 + r / n)}^{(n t)} = 1.9671513573$ .

$1.9671513573$

$r / n = 0.07, n t = 10, {(1 + r / n)}^{(n t)} = 1.9671513573$ .

3. Hesabu kiasi cha mwisho

$A = 26133.61$

$26133.61$

$13, 285 \cdot 1.9671513573 = 26133.61$ .

$26133.61$

$13, 285 \cdot 1.9671513573 = 26133.61$ .

$26133.61$

$13, 285 \cdot 1.9671513573 = 26133.61$ .

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Jifunze zaidi na Tiger

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Tiger algebra Suluhishaji

Ufumbuzi - Tiger algebra Suluhishaji

Maelezo kwa hatua

1. Weka fomula ya riba changamano

2. Hesabu kipengele cha ukuaji

3. Hesabu kiasi cha mwisho

Kwa nini kujifunza hii

Vigezo na mada

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