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Ufumbuzi - Tiger algebra Suluhishaji

1409.19

1409.19

Tazama hatua Jifunze zaidi na Tiger Jaribu hili:

Maelezo kwa hatua

1. Weka fomula ya riba changamano

$c i (1317, 7, 1, 1)$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 1, 317$ , $r = 7 %$ , $n = 1$ , $t = 1$ .

$c i (1317, 7, 1, 1)$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 1, 317$ , $r = 7 %$ , $n = 1$ , $t = 1$ .

$P = 1317, r = 7 %, n = 1, t = 1$

$\frac{7}{100} = 0.07$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 1, 317$ , $r = 7 %$ , $n = 1$ , $t = 1$ .

$A = P {(1 + r / n)}^{(n t)}$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 1, 317$ , $r = 7 %$ , $n = 1$ , $t = 1$ .

$N e x t c o m p u t e r / n, n t, a n d {(1 + r / n)}^{(n t)} .$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 1, 317$ , $r = 7 %$ , $n = 1$ , $t = 1$ .

2. Hesabu kipengele cha ukuaji

$\frac{r}{n} = 0.07$

$n t = 1$

${(1 + r / n)}^{(n t)}$

$r / n = 0.07, n t = 1, {(1 + r / n)}^{(n t)} = 1.07$ .

${(1 + r / n)}^{(n t)}$

${(1 + 0.07)}^{1} = 1.07$

$r / n = 0.07, n t = 1, {(1 + r / n)}^{(n t)} = 1.07$ .

$1.07$

$r / n = 0.07, n t = 1, {(1 + r / n)}^{(n t)} = 1.07$ .

3. Hesabu kiasi cha mwisho

$A = 1409.19$

$1409.19$

$1, 317 \cdot 1.07 = 1409.19$ .

$1409.19$

$1, 317 \cdot 1.07 = 1409.19$ .

$1409.19$

$1, 317 \cdot 1.07 = 1409.19$ .

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Tiger algebra Suluhishaji

Ufumbuzi - Tiger algebra Suluhishaji

Maelezo kwa hatua

1. Weka fomula ya riba changamano

2. Hesabu kipengele cha ukuaji

3. Hesabu kiasi cha mwisho

Kwa nini kujifunza hii

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